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strojnjashka [21]
3 years ago
7

Plz help me who can answer in a minand plz help me with a and b

Mathematics
2 answers:
Sloan [31]3 years ago
8 0
<span>Plz help me
who can answer in a min
and plz help me with a and b</span>
a) 1/5 or 20%
b) 83%


MatroZZZ [7]3 years ago
5 0
A) 20%

b) 83%

hope I helped ^^
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1. Escribe como potencia los siguientes productos y luego resuelve como se indica en el ejemplo. a) 6.6.6 = 6 3 = 216 f) 11.11=
alexandr402 [8]

Answer:

(Véase la explicación para mayores detalles/See the explanation for further details)

Step-by-step explanation:

a) Tres al cubo (Three to cube):

x = 3 \times 3 \times 3

x = 3^{3}

x = 27

b) Seis al cubo (Six to cube):

x = 6 \times 6 \times 6

x = 6^{3}

x = 216

c) Cinco al cuadrado (Five squared):

x = 5 \times 5

x = 5^{2}

x = 25

d) Ocho al cuadrado (Eight squared):

x = 8 \times 8

x = 8^{2}

x = 64

e) Dos a la quinta (Two to five):

x = 2 \times 2 \times 2 \times 2 \times 2

x = 2^{5}

x = 32

f) Diez a la cuarta (Ten to four):

x = 10\times 10 \times 10 \times 10

x = 10^{4}

x = 10000

3 0
3 years ago
James earned a total of $900 this week. this total was $20 less than four times the amount he earned last week. how much money d
Vladimir [108]
<span>4x – 20 = 900
4x = 900+20
4x = 920
x = 920/4
x = 230
he earned $230
                                   </span>
7 0
3 years ago
Hilary's Horse Hideaway is buying dirt to fill their circular training area. The training circle is 28 feet across. What is the
AnnZ [28]

Answer:

A = 615.75

cost = $107.08

Step-by-step explanation:

the training area = (28/2)^2*pi

training area = 615.75 square feet

615.75/5.75 = 107.08

$107.08

5 0
2 years ago
Please help me with number 1, thanks
tekilochka [14]
What don't you get about the problem ?
5 0
3 years ago
The Midpoint of AB dkdldl
Nutka1998 [239]
  • The Midpoint of AB is (1,0).

Given that:

  • In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).

To find:

  • The Midpoint of line AB.

So, according the question

We know that,

The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M ( \frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2} ).

Now from question,

We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.

So, we can say that

   A is (3,1) or x₁ = 3 and y₁ = 1.

   B (-1,-1) or x₂ = -1 and y₂ = -1.

∵ The coordinates of midpoint M (X,Y)

          X = \frac{x_1 + x_2}{2}

              = \frac{3-1}{2}

              = 2/2

          X = 1.

And

          Y = \frac{y_1 + y_2}{2}

              = \frac{1-1}{2}

              = 0/2

          Y = 0.

So, the midpoint of line AB is M (1,0)

To learn more about Midpoint of line, please click on the link;

brainly.com/question/14687140

#SPJ1

8 0
2 years ago
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