Hello!
The square root of 6 plus the square root of 8 equals
![\sqrt[4]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B3%7D%20)
, or for decimal form 6.92820323...
Brainliest please?
Answer:
I love algebra anyways
The ans is in the picture with the steps how i got it
(hope this helps can i plz have brainlist :D hehe)
Step-by-step explanation:
Answer:
2A/h - a = b
Step-by-step explanation:
Using A= 1/2(a+b)h
Divide both side by h
⇒A/h = 1/2(a + b)
Mutiply both sides by 2
⇒2A/h = a + b
Take the 2 over to the other side
2A/h - a = b
Keep in mind, that the (a) is not on the bottom, rather on its own
Step-by-step explanation:
Given,
1. The given expression is
.
We need to write it into exponential form.
We know that,
![\sqrt[a]{x} =x^{1/a}](https://tex.z-dn.net/?f=%5Csqrt%5Ba%5D%7Bx%7D%20%3Dx%5E%7B1%2Fa%7D)
Here, a = 10
So,
![\sqrt[10]{x^9}=(x^9)^{1/10}\\\\=x^{9\times \dfrac{1}{10}}\\\\=x^{9/10}\\\\=x^{0.1}](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7Bx%5E9%7D%3D%28x%5E9%29%5E%7B1%2F10%7D%5C%5C%5C%5C%3Dx%5E%7B9%5Ctimes%20%5Cdfrac%7B1%7D%7B10%7D%7D%5C%5C%5C%5C%3Dx%5E%7B9%2F10%7D%5C%5C%5C%5C%3Dx%5E%7B0.1%7D)
2.
![(\sqrt[4]{3y} )^3\\\\=((3y)^3)^{1/4}\\\\=3^{3\times \dfrac{1}{4}}\times y^{3\times \dfrac{1}{4}}\\\\=3^{3/4}y^{3/4}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B3y%7D%20%29%5E3%5C%5C%5C%5C%3D%28%283y%29%5E3%29%5E%7B1%2F4%7D%5C%5C%5C%5C%3D3%5E%7B3%5Ctimes%20%5Cdfrac%7B1%7D%7B4%7D%7D%5Ctimes%20y%5E%7B3%5Ctimes%20%5Cdfrac%7B1%7D%7B4%7D%7D%5C%5C%5C%5C%3D3%5E%7B3%2F4%7Dy%5E%7B3%2F4%7D)
Hence, this is the required solution.
Answer:
Expression:
Beetles after 16 years: 7984 beetles
Step-by-step explanation:
Since the population increases 30% annually every year on the population size of that year, then we need to use a compound interest formula which would be the following
A = P (1 + r/n) (nt)
A = the future amount
P = the initial amount
r = the annual increase rate (decimal)
n = the number of times that interest/increase is compounded per unit t
t = the number of years
Using the values in the question the expression for this scenario would be the following
120(1 + (0.30 / 1))^(1*16)
![120(1.3)^{16}](https://tex.z-dn.net/?f=120%281.3%29%5E%7B16%7D)
7984.99