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3 years ago

Whixh expression is eqivalent to the one shown?

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

5 0

I’m pretty sure it is 40 to the power of 9. I’m sorry If i get that wrong. But i’m pretty sure that it

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My question is 2/5 x 7/9 = ? Do you know what it equals?

GarryVolchara [31]

The answer would be 14/45

6 0

3 years ago

Question 13 (Essay Worth 8 points)

mixer [17]

9514 1404 393

Answer:

geometric sequence

Step-by-step explanation:

The terms of the sequence have a common ratio of -12/3 = -4, so the sequence is geometric. The general term is ...

an = 3(-4)^(n-1)

so the sum can be written as ...

$\displaystyle\sum_{n=0}^\infty3(-4)^n$

(Note the summation starts at n=0, corresponding to a first term of 3.)

3 0

3 years ago

Check screenshot. that is where the question is placed.

Marianna [84]

C is the awnser I believe correct me if I’m wrong

4 0

3 years ago

T - 6 1/3 = - 9 3/4 solve this !

Radda [10]

Answer: T=-3 5/12

Step-by-step explanation: 6 1/3-6 /13

6 1/3-9 3/4= -3 5/12

T= -3 5/12

3 0

3 years ago

Read 2 more answers

Please someone help me to prove this.

dem82 [27]

<h3>Answer :</h3>

We know that,

$\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}$

$\dag\bf\:sin2A=2sinA\:cosA$

___________________________________

Now, Let's solve !

$\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}$

$\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}$

$\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}$

$\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}$

$\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}$

$\leadsto\:\bf{tan(A+B)}$

5 0

3 years ago

Read 2 more answers