4. Barry wants to make a drawing that is 1/4 the size of the original. If the tree in the original drawing is 14 inches tall, ho
2 answers:
<u>Answer: </u>The height of the tree in Barry's drawing =
<u>Step-by-step explanation:</u>
Given: The height of the tree in the original drawing = 14 inches
Since, the height of the tree in the Barry's drawing is 1/4 the size of the original.
Then, the height of the tree in Barry's drawing =
Therefore, the height of the tree in Barry's drawing =
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Answer:
Yes
Step-by-step explanation:
First, look for the hypotenuse (diagonal) of the base of the box. We have the two legs: 13 inches and 35 inches.
Set up an equation using the Pythagorean theorem:
Solve for C:
169 + 1225 = C^2
1394 = C^2
C ≈ 37.34
Now that we have the diagonal of the base, we know can move on to find the value of the interior diagonal. We have two legs: 13 inches and 37.34 inches.
Again, set up an equation using the Pythagorean theorem, and solve for the new C:
1563.2756 = C^2
C = 39.54
The interior diagonal of the box is approximately 39.54 inches long, which is longer than Kylie's baton, which is 38 inches long. So, she can fit the baton in the box.
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Answer:
0.28cm/min
Step-by-step explanation:
Given the horizontal trough whose ends are isosceles trapezoid
Volume of the Trough =Base Area X Height
=Area of the Trapezoid X Height of the Trough (H)
The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)
The Volume of water in the trough at any time
=8h(8+2x)
V=64h+16hx
We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles
x/h=1/4
4x=h
x=h/4
Substituting x=h/4 into the Volume, V
h=3m,
dV/dt=25cm/min=0.25 m/min
=0.002841m/min =0.28cm/min
The rate is the water being drawn from the trough is 0.28cm/min.
Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.
Subtract 16 from both sides.
Divide by 4 on both sides.
The length of line segment PQ is 5 units.