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3 years ago

It is urgent plz answer

Mathematics

1 answer:

Mamont248 [21]3 years ago

7 0

Answer:

my class is 8 th is I don't now this answer

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The next stop on the road trip is the zoo! jacob goes to find his favorite animal, the giraffe. jacob wonders how tall the talle

lapo4ka [179]

1 foot = 12 inches
Height of Jacob = 5 feet 6 inches = 5 *12 + 6 = 66 inches
Jacob's shadow = 3 feet = 36 inches

giraffe's shadow = 5 feet 9 inches = 5 * 12 + 9 = 69 inches

by the ratio and proportion

∴ Height of Jacob/Jacob's shadow = Height of giraffe/giraffe's shadow

∴ 66/36 = Height of giraffe/69

∴ Height of giraffe = 69 * 66/36 = 126.5 inches = 10 feet 6.5 inches

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3 years ago

Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/3

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Answer:

y-y1=m(x-x1)

y-2=1/3(x-3)

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2 years ago

Point A is located at (-3, 9) and point B is located at (12,-10). Find the distance from point A to point B rounded to the neare

Nezavi [6.7K]

Answer:

Step-by-step explanation:

$\sqrt{(( - 10) - 9)^{2} + (12 - ( - 3)) ^{2} }$

$\sqrt{( - 19)^{2} + (15)^{2} }$

$\sqrt{361 + 225}$

$\sqrt{586}$

$24.2074$

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2 years ago

Samuel buys office supplies for his home buissness

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Answer:

What supplies?

Step-by-step explanation:

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2 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago