4(2x+3)(2x-3) is the answer
Answer and explanation:
They are not equivalent because if we simplify the second expression, the result isn't the same:
7(y×b)+3b
= 7(yb)+3b
=7yb + 3b
Therefore 7yb+3b≠7y+7b+3y
And even though you meant
7(y+b)+3b
=7y+7b+3b
=7y+10b
7y+10b≠10y+7b
By the inequality for x over on the right side if x is equal to or greater than 2 you use the bottom equation.
G(2) means x is 2.
Using the bottom equation replace the x’s with 2 and solve.
X^3 -9x^2 +27x-25
2^3 -9(2)^2+27(2)-25
Simplify:
8 -36 + 54-25 =1
The answer is A. 1
Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph
