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3 years ago

The solid shown are composed of prisms and half cylinders. Find the volume of the solid. Round to the nearest whole number.

Mathematics

1 answer:

viktelen [127]3 years ago

4 0

Dis too hard for me, plz vote brainliest and give me ur paypal for free answers

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^lets start off easy☺️^

butalik [34]

Answer:

mary=10 jack=15

Step-by-step explanation:

After 4 years Mary (x+4), Jack's age (x+5) + 4.

sum of the ages after 4 years :(x+4) + (x+5) +4=33

Simplifying the equation:

2x+13 = 33 ----->> 2x=20----->>>>x = 10 Mary's age

10 + 5 = 15 which is Jack's age.

7 0

3 years ago

the number of students in the four sixth-grade classs at northside school are 26, 19,34 and 21. Use properties to find the total

Aleks04 [339]

In this case all you do is add all the numbers, answer is 100

4 0

3 years ago

b. Two events are dependent if the occurrence of one event changes to occurrence of the second event. True or False

Naddika [18.5K]

Answer:

true

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

You work 4 hours on Saturday and 8 hours on Sunday. You also receive a $50 bonus. You earn $164. How much did you earn per hour?

Marina86 [1]

To find the hourly rate, we would first need to take the total earnings and subtract the bonus. $164 - $50 = 114 This gives us the total money earned for hourly work. Then we need to add the total hours worked: 4 + 8 = 12. Lastly, we need to take the total money earned and divide it by the total hours worked: 114 / 12 = 9.50 or $9.50 per hour. The equation could look like: 4h + 8h + $50 = $165

3 0

3 years ago

Read 2 more answers

Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke

Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that $\sqrt{3}=\frac{m}{n}$ where $m$ and $n$ are non negative integers, and the fraction $\frac{m}{n}$ is irreducible, i.e., the numbers $m$ and $n$ have no common factors.

Now, squaring the equality at the beginning we get that

$3=\frac{m^2}{n^2}$ (1)

which is equivalent to $3n^2=m^2$ . From this we can deduce that 3 divides the number $m^2$ , and necessarily 3 must divide $m$ . Thus, $m=3p$ , where $p$ is a non negative integer.

Substituting $m=3p$ into (1), we get

$3= \frac{9p^2}{n^2}$

which is equivalent to

$n^2=3p^2$ .

Thus, 3 divides $n^2$ and necessarily 3 must divide $n$ . Hence, $n=3q$ where $q$ is a non negative integer.

Notice that

$\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}$ .

The above equality means that the fraction $\frac{m}{n}$ is reducible, what contradicts our initial assumption. So, $\sqrt{3}$ is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, $r\in\mathbb{Q}$ , which is equivalent to say that $r=\frac{m}{n}$ where $m$ and $n$ are non negative integers. Also, assume that $k\in\mathbb{Z}$ . So, we want to prove that $k\cdot r\in\mathbb{Z}$ . Recall that an integer $k$ can be written as

$k=\frac{k}{1}$ .

Then,

$k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}$ .

Notice that the product $mk$ is an integer. Thus, the fraction $\frac{mk}{n}$ is a rational number. Therefore, $k\cdot r\in\mathbb{Q}$ .

3. Let us prove by <em>reductio ad absurdum</em> that the sum of a rational number and an irrational number is an irrational number. So, we have $x$ is irrational and $p\in\mathbb{Q}$ .

Write $q=x+p$ and let us suppose that $q$ is a rational number. So, we get that

$x=q-p$ .

But the subtraction or addition of two rational numbers is rational too. Then, the number $x$ must be rational too, which is a clear contradiction with our hypothesis. Therefore, $x+p$ is irrational.

7 0

4 years ago