Answer:
The answer to this is: y = (x - 6)² - 28
Step-by-step explanation:
The first step is to make sure the coefficient in front of x² is 1. If it isn't, just divide the whole equation by the coefficient. In this case, you don't need to do any division because you just have x²
Group the first two terms involving x² and x:
(x² - 12x) + 8
Now complete the square as follows:
a. Take the coefficient in front of x --> -12
b. Halve it --> -6
c. Square it --> (-6)² = 36
d. Add this and subtract it
(x² - 12x + 36 - 36) + 8
Take the negative number outside the parentheses:
(x² - 12x + 36) - 36 + 8
(x² - 12x + 36) - 28
The part in parentheses is a perfect square so rewrite it as such. If you need help refer back to step b.
(x - 6)(x - 6) - 28
(x - 6)² - 28
P.S. Vertex form is:
(x - h)² + k
In that form, the vertex is (h, k). In your case, the vertex of the parabola would be (6, -28).
Answer:
y = (x - 6)² - 28
