Solve for x: 2x^5/3-22=464 a) x = 28 b) x = 27 c) x = ±27 d) x = ±28
1 answer:
Answer:
<h3>x = 27</h3>
Step-by-step explanation:
Given the expression
, we are to find the value of x in the expression. This is as shown below;

add 22 to both sides


divide both sides by 2

raise both sides to the power of 3/5
![(x^{5/3})^{3/5} = (243)^{3/5}\\x = (\sqrt[5]{243}) ^3\\x = 3^3\\x = 27](https://tex.z-dn.net/?f=%28x%5E%7B5%2F3%7D%29%5E%7B3%2F5%7D%20%3D%20%28243%29%5E%7B3%2F5%7D%5C%5Cx%20%3D%20%28%5Csqrt%5B5%5D%7B243%7D%29%20%5E3%5C%5Cx%20%3D%203%5E3%5C%5Cx%20%3D%2027)
Hence the value of x is 27
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