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Naya [18.7K]
3 years ago
12

Given that 2x + 1 =5, what is the value of (x+3)^3

Mathematics
2 answers:
Anika [276]3 years ago
7 0

Answer:

The value of (x + 3)³ is 125.

Step-by-step explanation:

First, we have to find the value of x.

To do so, start with the first equation, 2x + 1 = 5.

We can easily solve this equation to find the value of x.

First, start by subtracting 1 from each side.

This leaves us with 2x = 4.

Next, divide by two on each side.

This will leave us with the answer x = 2.

Now we know the value of x = 2.

All that's left to do is substitute the value of x, 2, for x.

First, start with the second equation (x + 3)³.

We know that x is equal to 2, so we can enter 2 for x.

We then have the equation (2 + 3)³.

Next, solve.

Add the 2 and the 3 together.

Now, the equation is 5³.

5³ is equal to 5 · 5 · 5

5 · 5 · 5 = 125

To sum up,

We found out that x = 2

Using 2 for x, we found out that (x + 3)³ is equal to 125.

Alla [95]3 years ago
5 0

Answer: 125

Step-by-step explanation:

First, solve for x in the first equation.

1) Subtract 1 from both sides.

2x = 4

2) Divide by 2 on both sides.

x = 2

Next, substitute the value of x into the second expression.

(2 + 3)^3

= 5^3

= 125

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Ms Lucas has 9 cases of crayon with 52 boxes in each case Ms Bruns has 6 cases of crayon with a 104 in each case How many boxes
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Answer:

1092

Step-by-step explanation:

Step one:

given data

Ms Lucas has 9 cases of crayon with 52 boxes in each case

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The total crayon is

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5 0
3 years ago
A study on the population of wolves is being done in a county to determine how the number of wolves has changed over time. The p
mr_godi [17]

Answer:

<h2>The year is 2010.</h2>

Step-by-step explanation:

The population of wolves is given by P(t) = 80(0.98)t.

The study has began in the year of 2000 and will end in 2020.

The difference between 2000 and 2009 is 9 years and the difference between 2009 and 2020 is 11 years.

Hence, the maximum value of t is 11.

The domain is 0 \leq t \leq 11.

The population will be 80, that is P(t) = 80.

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3 0
3 years ago
A total of 800 pre-sale tickets and tickets at the gate were sold to football city championship game. If the number of tickets s
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The number of presale tickets sold is 271

<em><u>Solution:</u></em>

Let "p" be the number of presale tickets sold

Let "g" be the number of tickets sold at gate

<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>

Therefore,

Presale tickets + tickets sold at gate = 800

p + g = 800 ------ eqn 1

<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>

Therefore,

Number of tickets sold at gate = twice the number of pre-sale tickets - 13

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<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 2 in eqn 1

p + 2p - 13 = 800

3p -13 = 800

3p = 800 + 13

3p = 813

p = 271

Thus 271 presale tickets were sold

4 0
3 years ago
Does anyone have the answer to this? <br> 3(x+2)-7 = 5x + 7.
Aleks04 [339]

Answer:

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Step-by-step explanation:

3 0
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