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3 years ago

Given that 2x + 1 =5, what is the value of (x+3)^3

Mathematics

2 answers:

Anika [276]3 years ago

7 0

Answer:

The value of (x + 3)³ is 125.

Step-by-step explanation:

First, we have to find the value of x.

To do so, start with the first equation, 2x + 1 = 5.

We can easily solve this equation to find the value of x.

First, start by subtracting 1 from each side.

This leaves us with 2x = 4.

Next, divide by two on each side.

This will leave us with the answer x = 2.

Now we know the value of x = 2.

All that's left to do is substitute the value of x, 2, for x.

First, start with the second equation (x + 3)³.

We know that x is equal to 2, so we can enter 2 for x.

We then have the equation (2 + 3)³.

Next, solve.

Add the 2 and the 3 together.

Now, the equation is 5³.

5³ is equal to 5 · 5 · 5

5 · 5 · 5 = 125

To sum up,

We found out that x = 2

Using 2 for x, we found out that (x + 3)³ is equal to 125.

Alla [95]3 years ago

5 0

Answer: 125

Step-by-step explanation:

First, solve for x in the first equation.

1) Subtract 1 from both sides.

2x = 4

2) Divide by 2 on both sides.

x = 2

Next, substitute the value of x into the second expression.

(2 + 3)^3

= 5^3

= 125

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Answer:

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Step-by-step explanation:

Given:

Sample1: 98.1 98.8 97.3 97.5 97.9

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Sample 1 Sample 2 Difference d

98.1 98.7 -0.6

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To find:

Find the values of $\frac{}{d}$ and $s_{d}$

d overbar ( $\frac{}{d}$ ) is the sample mean of the differences which is calculated by dividing the sum of all the values of difference d with the number of values i.e. n = 5

$\frac{}{d}$ = ∑d/n

= (−0.6 −0.6 −0.4 +0.4 −0.1) / 5

= −1.3 / 5

$\frac{}{d}$ = −0.26

s Subscript d is the sample standard deviation of the difference which is calculated as following:

$s_{d}$ = √∑( $d_{i}$ - $\frac{}{d}$ )²/ n-1

$s_{d}$ =

√ $(-0.6 - (-0.26))^{2} + (-0.6 - (-0.26))^{2} + (-0.4 - (-0.26))^{2} + (0.4-(-0.26))^{2} + (-0.1 - (-0.26))^{2} / 5-1$

= √ (−0.6 − (−0.26 ))² + (−0.6 − (−0.26))² + (−0.4 − (−0.26))² + (0.4 −

(−0.26))² + (−0.1 − (−0.26))² / 5−1

= $\sqrt{\frac{0.1156 + 0.1156 + 0.0196 + 0.4356 + 0.0256}{4} }$

= $\sqrt{\frac{0.712}{4} }$

= $\sqrt{0.178}$

= 0.4219

$s_{d}$ = 0.4219

Subscript d represent

μ $_{d}$ represents the mean of differences in body temperatures measured at 8 AM and at 12 AM of population.

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