.<br><br> help me i don't know how to do this. (algebra 2)

The point A(-2, 3) is translated using T: (x,y) = (x + 4, y + 2).

Charra [1.4K]

Answer: Choice D) $2\sqrt{5}$

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Work Shown:

Point A starts at (-2,3) and moves to (2,5) after applying the translation rule of "shift 4 to the right, 2 up".

Use the distance formula to find the distance from (-2,3) to (2,5)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-2-2)^2 + (3-5)^2}\\\\d = \sqrt{(-4)^2 + (-2)^2}\\\\d = \sqrt{16 + 4}\\\\d = \sqrt{20}\\\\d = \sqrt{4*5}\\\\d = \sqrt{4}*\sqrt{5}\\\\d = 2\sqrt{5}\\\\d \approx 4.472136\\\\$

6 0

3 years ago

Sketch the graph of the function

Ostrovityanka [42]

Sent a picture of the solution to the problem (s). I usually graph at least 5 points. Usually one is 0 and I go up from zero and down from zero.

7 0

3 years ago

Elliot put 7 cups of tea into the pitcher shown. How many more cups of tea does he need to fill the pitcher?

sukhopar [10]

Answer: The Answer would be 9.

Step-by-step explanation:

Since there is only 7 and the empty space is 2 cups, The answer would be 9. 7 + 2 = 9.

8 0

2 years ago

A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of

hram777 [196]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ <u>Ratio of two angles are 6:13.</u>

So, let the one angle be $\sf{6x}$ and another be $\sf{13x.}$

As we know that,

Sum of all interior angles of a quadrilateral = $\sf\pink{360°.}$

So let's sum up the given angles,

$\rightarrow$ $\sf{222°+81°+6x+13x \:=\: 360°}$

$\rightarrow$ $\sf{303+19x \:=\: 360°}$

$\rightarrow$ $\sf{19x \:=\: 360-303}$

$\rightarrow$ $\sf{19x \:=\: 57}$

$\rightarrow$ $\sf{x \:=\: \frac{19}{57}}$

$\rightarrow$ $\sf{x \:=\: 3}$

Hence, $\sf{x \:=\: 3}$

So, First angle $\sf{= \:6x\: = \:6×3 \:=}$ $\sf\purple{18°.}$

Second angle $\sf{= \:13x\: = \:13×3 \:=}$ $\sf\purple{39°.}$

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Hope it helps you:)

3 0

2 years ago

The given line passes through the points (-4,-3) and (4,

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

first we gotta find the slope of the first line

(-4,-3),(4,1)

slope = (y2 - y1) / (x2 - x1) = (1- (-3) / (4 - (-4) = (1 + 3) / (4 + 4) = 4/8 = 1/2

so the slope is 1/2.....so we are looking for a line that is perpendicular....perpendicular lines have negative reciprocal slopes...all that means is flip the slope and change the sign....so the slope we need is :

1/2....flip it....2/1.....change the sign....-2.....we need a -2 slope

y - y1 = m(x - x1)

slope = -2

(-4,3)...x1 = -4 and y1 = 3

now sub

y - 3 = -2(x - (-4) =

y - 3 = -2(x + 4) <=====

6 0

3 years ago

. help me i don't know how to do this. (algebra 2)