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2 years ago

10

Which of the following is NOT a period of the Middle Ages?

Computers and Technology

1 answer:

frez [133]2 years ago

5 0

High middle ages is the answer

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The ________ method displays a message to the user and contains one button.

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3 years ago

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3 years ago

Suppose users share a 1-Gbps link. Also, suppose each user requires 200 Mbps when transmitting, but each user only transmits 30

V125BC [204]

Answer:

The answer is "5 users and 1 block".

Explanation:

In Option a:

Bandwidth total $= 1-Gbps \times 1000$

$= 1,000 \ Mbps$

Any User Requirement $= 200 \ Mbps$

The method for calculating the number of approved users also is:

Now, calculate the price of each person for overall bandwidth and demands,

$\text{Sponsored user amount} = \frac{\text{Bandwidth total}}{\text{Each user's requirement}}$

$=\frac{1000}{200}\\\\=\frac{10}{2}\\\\= 5 \ users$

In Option b:

$\text{blocking probability} = \frac{link}{\text{1-Gbps} = 10^9 \frac{bits}{sec}}$

$\ let = 0.05 = \frac{100}{20} \\\\\text{blocking probability} = \frac{ 200 \times 10^6}{\frac{100}{20}}$

$= \frac{ 200 \times 10^6 \times 20 }{100}\\\\= \frac{ 2 \times 10^6 \times 20 }{1}\\\\= 40 \times 10^6 \\\\$

mean user $= 25 \times \frac{1}{20} \\\\$

$= 1.25$

max user $= \frac{10^9}{40 \times 10^6} \\\\$

$= \frac{10^9}{4 \times 10^7} \\\\ = \frac{10^2}{4} \\\\ = \frac{100}{4} \\\\= 25 \\\\ =\ \ 1 \ \ block \\\\$

3 0

2 years ago