$f'(x_0)=\lim\limits_{h\to0}\dfrac{f(x_0+h)-f(h)}{h}=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=\dfrac{6}{x};\ x_0=2\\\\subtitute\\\\f'(2)=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-\frac{6}{2}}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-3}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6-3x}{x}}{x-2}=\lim\limits_{x\to 2}\dfrac{6-3x}{x(x-2)}\\\\=\lim\limits_{x\to2}\dfrac{-3(x-2)}{x(x-2)}=\lim\limits_{x\to2}\dfrac{-3}{x}=-\dfrac{3}{2}=-1.5\\\\\\An swer:\boxed{f'(2)=-1.5}$

8 0

3 years ago

Lisa's favorite chocolate candies are wrapped in the shape of a triangular prism with shiny gold paper as shown below. if all si

ANEK [815]

It is 96.
triangular part:
1/2 a* g = 1/2 * 8 * 3 = 12 = d
c = √(3²+(8/2)²)=5
square part:2*c + 2*b = 7*2 + 5 * 2 = 24 = e
since you have 2x triangular and 3x squares

2*d+ 3*e = 96

7 0

3 years ago

Read 2 more answers

A company that makes trail mix uses 1 3/8

leonid [27]

Is it 17.75 cuz what i got

7 0

3 years ago

∠1 and​ ​ ∠2 ​ ​are complementary angles. m∠1=52° What is the measure of ​ ∠2 ​​?

∠1 and ∠2 are complementary angles. m∠1=52° What is the measure of ∠2 ?