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nata0808 [166]
3 years ago
13

True Or False

Mathematics
1 answer:
Margarita [4]3 years ago
7 0
Yes I believe it does refer to os
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For some postive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770. The value of Z is
Talja [164]

Answer:

1.16

Step-by-step explanation:

Given that;

For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.

This implies that:

P(0<Z<z) = 0.3770

P(Z < z)-P(Z < 0) = 0.3770

P(Z < z) = 0.3770 + P(Z < 0)

From the standard normal tables , P(Z < 0)  =0.5

P(Z < z) = 0.3770 + 0.5

P(Z < z) =  0.877

SO to determine the value of z for which it is equal to 0.877, we look at the

table of standard normal distribution and locate the probability value of 0.8770. we advance to the  left until the first column is reached, we see that the value was 1.1.  similarly, we did the same in the  upward direction until the top row is reached, the value was 0.06.  The intersection of the row and column values gives the area to the two tail of z.   (i.e 1.1 + 0.06 =1.16)

therefore, P(Z ≤ 1.16 ) = 0.877

8 0
3 years ago
A washer and a dryer cost $799 combined. The washer costs $49 more than the dryer. What is the cost of the dryer?
rusak2 [61]
A) w + d = 799
B) w = d + 49
B) w -d = 49

Adding A & B
2w = 848

washer = 424

w -49 = d
dryer = 424 -49
dryer = 375


4 0
3 years ago
Greatest common factor of 3 and 2
Andreas93 [3]
Gcd(3,2)=1   Hope this helps!!

(The answer is 1)
4 0
3 years ago
Read 2 more answers
PLEASE HELP 100 POINTS.
aalyn [17]

Wait I don’t understand what u need
3 0
3 years ago
Read 2 more answers
Solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!​
FromTheMoon [43]

Answer: t\in [\dfrac{1}{4},2]

Step-by-step explanation:

Given

Inequality is 4t^2\leq9t-2

Taking variables one side

\Rightarrow 4t^2-9t+2\leq0\\\Rightarrow 4t^2-8t-t+2\leq0\\\Rightarrow 4t(t-2)-1(t-2)\leq0\\\Rightarrow (4t-1)(t-2)\leq0

Using wavy curve method

t\in [\dfrac{1}{4},2]

3 0
3 years ago
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