Change the numbers into improper fractions then subtract
Answer:
44 mph
Step-by-step explanation:
Given that:
Before lunch :
Time taken = 2hrs ; at speed = x mph
After lunch :
Time taken = 3hrs ; at speed = x + 10 mph
Total distance covered = 250 miles :
Distance = speed * time
(2 * x) + (3 * (x + 10)) = 250
2x + 3x + 30 = 250
5x + 30 = 250
5x = 250 - 30
5x = 220
x = 220/ 5
x = 44 mph
Rate before lunch is 44mph
This is the concept of areas of solid materials; the surface area of the cylinder whose radius is 2.5 cm and lateral area is 20 pi cm^2 will be: Surface area of cylinder is given by:
SA=(area of cyclic sides)+(lateral area)
SA=2πr^2+πrl
Area of the cyclic sides will be:
Area=2πr^2
=2*π*2.5^2
=12.5π cm^2
The lateral area is given by:
Area=20π cm^2
Therefore the surface area of cylinder will be:
SA=(12.5π+20π) cm^2
SA=32.5π cm^2
The answer is 32.5π cm^2
A line segment that goes from one side of the circle to the other side of the circle and doesn't go through the center is called chord of circle.
Since,
The chord of a circle can be defined as the line segment joining any two points on the circumference of the circle.
The diameter is the length of the line through the center that touches two points on the edge of the circle.
So, we can say that every diameter of a circle is always called chord (longest chord) but every chord of the circle is not a diameter because the diameter passes to the circle's center but it not necessay that evey chord will pass through the center of the circle. Some, line segment goes from one side of the circle to the other side and doesn't pass through centre then for this case the line segment is called chord of the circle.
Hence, a line segment that goes from one side of the circle to the other side of the circle and doesn't go through the center is called chord of the circle.
Find out more information about chord of circle here:
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<span>Simplifying
3a2 + -2a + -1 = 0
Reorder the terms:
-1 + -2a + 3a2 = 0
Solving
-1 + -2a + 3a2 = 0
Solving for variable 'a'.
Factor a trinomial.
(-1 + -3a)(1 + -1a) = 0
Subproblem 1Set the factor '(-1 + -3a)' equal to zero and attempt to solve:
Simplifying
-1 + -3a = 0
Solving
-1 + -3a = 0
Move all terms containing a to the left, all other terms to the right.
Add '1' to each side of the equation.
-1 + 1 + -3a = 0 + 1
Combine like terms: -1 + 1 = 0
0 + -3a = 0 + 1
-3a = 0 + 1
Combine like terms: 0 + 1 = 1
-3a = 1
Divide each side by '-3'.
a = -0.3333333333
Simplifying
a = -0.3333333333
Subproblem 2Set the factor '(1 + -1a)' equal to zero and attempt to solve:
Simplifying
1 + -1a = 0
Solving
1 + -1a = 0
Move all terms containing a to the left, all other terms to the right.
Add '-1' to each side of the equation.
1 + -1 + -1a = 0 + -1
Combine like terms: 1 + -1 = 0
0 + -1a = 0 + -1
-1a = 0 + -1
Combine like terms: 0 + -1 = -1
-1a = -1
Divide each side by '-1'.
a = 1
Simplifying
a = 1Solutiona = {-0.3333333333, 1}</span>