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gregori [183]
3 years ago
10

Garden hose emits 9 quarts of water in 6 seconds how long will it take the hose to emit 12 quarts?

Mathematics
2 answers:
Vlada [557]3 years ago
5 0

Answer:

64

Step-by-step explanation:

ummmmmmmmmmmmmmm

Assoli18 [71]3 years ago
3 0
Answer : 24

Explanation: when you start with 9 and you add up to 12 which is 3 and you multiply 6 3 times which gets you 24 seconds

Hope this helps
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Find the length of side AB, give your answer to 1 decimal place
Alex_Xolod [135]

Answer:

5.6 = AB

Step-by-step explanation:

Since this is a right triangle, we can use trig functions to find the length of AB

Cos theta = opp side/ hypotenuse

cos 62 = AB / BC

cos 62 = AB /12

Multiply each side by 12

12 cos 62 = AB

5.633658753 = AB

Rounding to 1 decimal place

5.6 = AB

We can also find AC

sin theta = opp side/ hypotenuse

sin 62 = AC / BC

sin 62 = AC /12

Multiply each side by 12

12 sin 62 = AC

10.59537111 = AC

Rounding to 1 decimal place

10.6 = AC

5 0
3 years ago
Read 2 more answers
The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas
iren [92.7K]

For the last part, you have to find where f'(t) attains its maximum over 0\le t\le8. We have

f'(t)=-6\sin3t+6\cos2t

so that

f''(t)=-18\cos3t-12\sin2t

with critical points at t such that

-18\cos3t-12\sin2t=0

3\cos3t+2\sin2t=0

3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0

\cos t(3\cos^2t-9\sin^2t+4\sin t)=0

\cos t(12\sin^2t-4\sin t-3)=0

So either

\cos t=0\implies t=\dfrac{(2n+1)\pi}2

or

12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi

where n is any integer. We get 8 solutions over the given interval with n=0,1,2 from the first set of solutions, n=0,1 from the set of solutions where \sin t=\dfrac{1+\sqrt{10}}6, and n=1 from the set of solutions where \sin t=\dfrac{1-\sqrt{10}}6. They are approximately

\dfrac\pi2\approx2

\dfrac{3\pi}2\approx5

\dfrac{5\pi}2\approx8

\sin^{-1}\dfrac{1+\sqrt{10}}6\approx1

2\pi+\sin^{-1}\dfrac{1+\sqrt{10}}6\approx7

2\pi+\sin^{-1}\dfrac{1-\sqrt{10}}6\approx6

4 0
3 years ago
24. A metal coin is located at (18, 10). How much closer or farther from Ann is the coin than the jewelry?​
Vinvika [58]

Answer:

10.5

Step-by-step explanation:

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3 years ago
Millie works 8 hours each Saturday and earns £50. On a Saturday she spends £2.75 on bus fares and £4.25 on lunch. She allocated
jekas [21]
(50 - (2.75 + 4.25)) / 6 = (50 - 7) / 6 = 43/6 = 7.17 per day
6 0
3 years ago
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I think it’s 85.71%........I am not sure
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