Answer:
(For the first two questions I do believe that you will need a protractor to calculate the angles.)
15) 
measures out to -70° in order to display that the angle would be in quadrant IV (the bottom right quadrant.)
The first image attached shows where the angle should be located.
16) 
is equal to 60° (the line you draw will be in quadrant 1 (the top right quadrant))
17) 350° is 
or 6.11 (the answer depends on the format the professor wants.)
18) 240° is 
radians or -4.19 (I am rounding to the nearest hundredths place the unsimplified answer is −4.18879020...)
Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
y=5
Step-by-step explanation:
Answer:
picture of graph is attached. lmk if ur getting these right. its been a while since I've dont this
