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3 years ago

What is 41 divided by 496

Mathematics

1 answer:

Ludmilka [50]3 years ago

3 0

41 / 496 =
0.082661290322581

496 / 41 = 12.09756097560976

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How do you solve this question?

Lady bird [3.3K]

Answer:

$\large \boxed{\sf \ \ \ 2x-ln(1-x) \ \ \ }$

Step-by-step explanation:

Hello,

for any real x different from 1

$\dfrac{3-2x}{1-x}=\dfrac{2-2x+1}{1-x}\\\\=\dfrac{2(1-x)+1}{1-x}\\\\=2\dfrac{1-x}{1-x}+\dfrac{1}{1-x}\\\\=2+\dfrac{1}{1-x}$

if f(x)=2x

f'(x)=2

if g(x)=-ln(1-x)

$g'(x)=\dfrac{-1*-1}{1-x}=\dfrac{1}{1-x}$

So antiderivative of

$\dfrac{3-2x}{1-x}=2+\dfrac{1}{1-x}$

2x-ln(1-x)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0

3 years ago

For Part A, my answer was 435 since I multiplied 5 x 87 = 435.

maksim [4K]

Answer:

a. 36.25 ft

b. 45 ft

Step-by-step explanation:

GIVE YOUR ANSWER IN FEET !!! as the problem statement says.

not in inches. when you use the scale factor with inches, you get inches as result. then you need to convert them to feet.

how many inches in 1 ft ?

12 !

so, you need to divide your results by 12 to get the feet.

3 0

3 years ago

Which is the equation of a hyperbola with directrices at y = ±2 and foci at (0, 4) and (0, −4)?

Advocard [28]

Answer:

Step-by-step explanation:

First off, I'm assuming that when you said "directrices" you mean the oblique asymptotes, since hyperbolas do not have directrices they have oblique asymptotes.

If we plot the asymptotes and the foci, we see that where the asymptotes cross is at the origin. This means that the center of the hyperbola is (0, 0), which is important to know.

After we plot the foci, we see that they are one the y-axis, which is a vertical axis, which means that the hyperbola opens up and down instead of sideways. Knowing those 2 characteristics, we can determine that the equation we are trying to fill in has the standard form

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1$

We know h and k from the center, now we need to find a and b. Those values can be found from the asymptotes. The asymptotes have the standard form

y = ± $\frac{a}{b}(x-h)+k$

Filling in our asymptotes as they were given to us:

y = ± $\frac{2}{1}(x-0)+0$ where a is 2 and b is 1. Now we can write the formula for the hyperbola!:

$\frac{(y-0)^2}{4}-\frac{(x-0)^2}{1}=1$ which of course simplifies to

$\frac{y^2}{4}-\frac{x^2}{1}=1$

4 0

4 years ago

Will give brainlest help please

julia-pushkina [17]

Answer:

If your solving by sub. then it would come out as

a=-2

b=1

c=-2

hope it helps if not please ask again

Step-by-step explanation:

3 0

3 years ago

A roller coaster's height from the ground is modeled by r(t) = 4sin(4t)+25 where t is time in minutes. A Ferris wheel's height f

GuDViN [60]

Un cateto, en geometría, es cualquiera de los dos lados menores de un triángulo rectángulo, los que conforman el ángulo recto. El lado de mayor medida se denomina hipotenusa –el que es opuesto al ángulo recto. La denominación de catetos e hipotenusa se aplica a los lados de los triángulos rectángulos exclusivamente.

3 0

3 years ago

What is 41 divided by 496​

What is 41 divided by 496