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3 years ago

15

The elevator in the empire state building goes up to the 103rd floor and descends to -5 for parking. What does 0 represent in th

e context of this situation?

1 answer:

Inessa05 [86]3 years ago

5 0

0 could possibly represent ground level in this situation.

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Given z=f(x,y),x=x(u,v),y=y(u,v), with x(4,1)=5 and y(4,1)=2, calculate zv(4,1) in terms of some of the values given in the tabl

Yuliya22 [10]

$z=f(x(u,v),y(u,v))\implies z_v=f_xx_v+f_yy_v$

$z_v(4,1)=f_x(5)x_v(4,1)+f_y(2)y_v(4,1)$

No table = incomplete answer

3 0

3 years ago

Which is the solution set to the inequality (4x-3)(2x-1)&gt=0?

Serjik [45]

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

4x - 3 = 0 2x - 1 = 0

x = $\frac{3}{4}$ x = $\frac{1}{2}$

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------ $\frac{1}{2}$ ------ $\frac{5}{8}$ ------ $\frac{3}{4}$ ------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1] = ( - )( - ) = + THIS WORKS!

Test Point $\frac{5}{8}$ : [4( $\frac{5}{8}$ ) - 3][2( $\frac{5}{8}$ ) - 1] = ( - )( + ) = - <em>This does NOT work</em>

Test Point 1: [4(1) - 3][2(1) - 1] = ( + )( + ) = + THIS WORKS!

Answer: x ≤ $\frac{1}{2}$ or x ≥ $\frac{3}{4}$

Interval Notation: (-∞, $\frac{1}{2}$ ] U [ $\frac{3}{4}$ , ∞)

Graph: ←------ $\frac{1}{2}$ $\frac{3}{4}$ --------→

5 0

3 years ago

In ΔPQR, what is the m∠Q? Enter your answer in the box.

Orlov [11]

Answer:

105°

Step-by-step explanation:

11x-5 + 6x+5 + x = 180

18x = 180

x = 10

m∠Q = 11(10)-5 = 110-5 = 105°

8 0

3 years ago

Karen took a science test where each correct answer was worth 2.5 points. She also correctly answered the bonus question worth 8

klasskru [66]

Answer: 16 is your answer hope this helped

Step-by-step explanation:

pleas make brainly

3 0

3 years ago

Read 2 more answers

Awarding road contracts. A state Department of Transportation (DOT) recently claimed that each of five bidders received equal co

Sveta_85 [38]

Answer:

a) Hence, the probability of this event occurring if, in fact, the DOT's claim is true

= 3/10 = 0.3

Step-by-step explanation:

a) The concept applied here is combinatorics ; nCr = n!/(n - r)!r!

we are told that out of 5bidders, Three of the bidders were large construction conglomerates

and two were small specialty contractors.

selecting two recipients with tree of the bidders were large construction conglomerates 3C2

= 3!/(3-2)!2!

= 3

Similarly, selecting the two small casualty contractor from the total of 5bidders = 5C2

= 5!/(5-2)!2!

= 10

Hence, the probability of this event occurring if, in fact, the DOT's claim is true

= 3/10 = 0.3

b) if DOTs claim is not true ( probability of failure) = 1 - 0.3

= 0.7 , this value implies that the probability 0.3 is largely compatible and a compliment of the 0.7 and as such it is consistent with the DOTs claim that the selection was random.

7 0

3 years ago