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vagabundo [1.1K]
3 years ago
6

In 50 gram portion of cereal 8 grams of it are sugar which of the following represents the present of the 50 grams that is sugar

Mathematics
2 answers:
Lisa [10]3 years ago
6 0

Answer:

C = 8/50 = 0.16 * 100 = 16

Step-by-step explanation:

kipiarov [429]3 years ago
5 0

Answer:

C

Step-by-step explanation:

8/50= 0.16

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What is the area of a circle with diameter 15 cm? Round your answer to the nearest tenth.
Len [333]

Answer:

176.8

Step-by-step explanation: first you have to find the radius by finding the half of 15 which is calculated to be 7.5

and the formula to find the area is A=\pi 7.5^{2} \\

6 0
2 years ago
1.The length of a ship model is 3% of the length of the actual ship. The model is 1.5 M long. How long is the actual ship? ____M
Vilka [71]
We have to find 100% of the number. We can use proportion to get it
3% -----------1.5m
100% -------- x
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3*x=1.5*100
3x=150      /:3 divide both sides by 3
x=50m

2. Similar situation
40% ------------1000
100% -----------x
crossmultiply
40*x=100*1000
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8 0
3 years ago
GIVING BRAINLIEST!!! <br><br> What’s 2 x2
Papessa [141]

Answer:

4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
PRE -CALC QUESTION PLS HELP
Delicious77 [7]
For this case we have the following vector:
 v = (- 8, 2)
 Using product point we have:
 v.v = (-8, 2). (- 8, 2)
 v ^ 2 = (-8) * (- 8) + (2) * (2)
 v ^ 2 = 64 + 4
 v ^ 2 = 68
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 v = root (4 * 17)
 v = 2 * root (17)
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option c
6 0
3 years ago
A normally distributed population has mean 57,800 and standard deviation 750. Find the probability that a single randomly select
Stels [109]

Answer:

(a) Probability that a single randomly selected element X of the population is between 57,000 and 58,000 = 0.46411

(b) Probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = 0.99621

Step-by-step explanation:

We are given that a normally distributed population has mean 57,800 and standard deviation 75, i.e.; \mu = 57,800  and  \sigma = 750.

Let X = randomly selected element of the population

The z probability is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)  

(a) So, P(57,000 <= X <= 58,000) = P(X <= 58,000) - P(X < 57,000)

P(X <= 58,000) = P( \frac{X-\mu}{\sigma} <= \frac{58000-57800}{750} ) = P(Z <= 0.27) = 0.60642

P(X < 57000) = P( \frac{X-\mu}{\sigma} < \frac{57000-57800}{750} ) = P(Z < -1.07) = 1 - P(Z <= 1.07)

                                                          = 1 - 0.85769 = 0.14231

Therefore, P(31 < X < 40) = 0.60642 - 0.14231 = 0.46411 .

(b) Now, we are given sample of size, n = 100

So, Mean of X, X bar = 57,800 same as before

But standard deviation of X, s = \frac{\sigma}{\sqrt{n} } = \frac{750}{\sqrt{100} } = 75

The z probability is given by;

           Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)  

Now, probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = P(57,000 < X bar < 58,000)

P(57,000 <= X bar <= 58,000) = P(X bar <= 58,000) - P(X bar < 57,000)

P(X bar <= 58,000) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{58000-57800}{\frac{750}{\sqrt{100} } } ) = P(Z <= 2.67) = 0.99621

P(X < 57000) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{57000-57800}{\frac{750}{\sqrt{100} } } ) = P(Z < -10.67) = P(Z > 10.67)

This probability is that much small that it is very close to 0

Therefore, P(57,000 < X bar < 58,000) = 0.99621 - 0 = 0.99621 .

7 0
3 years ago
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