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zmey [24]
3 years ago
11

I need help with this question please and thank you

Mathematics
1 answer:
inna [77]3 years ago
5 0

d-13=5 is actually suppose to be solved liek this:

d - 13 = 5

   +13   +13

The absoulte value of 13 is 13, it is negative so you have to add 13 to get to 0 so it can be cancelled out.

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Deon bought a desktop computer and a laptop computer. Before finance charges, the laptop cost $250 less than the desktop. He pai
zysi [14]

Answer:

300

Step-by-step explanation:

Let x = cost of desktop computer; then x - 250 = cost of laptop computer

converting % to decimals, 9% = 0.09 and 6% = 0.06

Then, 0.09x + (x - 250)0.06 = $300

0.09x + 0.06x - 15 = $300

0.15x = $315

x = $2100

then x - 250 = $1850

Proof: $2100•0.09 + 1850•0.06 = $189 + $111 = $300

7 0
3 years ago
Five times a number is the same as two times a number added 21
Vera_Pavlovna [14]

Answer:

Our number is 7.

Step-by-step explanation:

We also know that it's 2x + 21 = 5x.

Now we solve.

21 = 5x - 2x

21 = 3x

7 = x

7 0
3 years ago
Find cosine of angle a ​
Hunter-Best [27]

Answer:

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Step-by-step explanation:

6 0
3 years ago
The polygons are similar. Find the missing side length. NO LINKS!!!!​
timurjin [86]

Answer:

CD = 27

Step-by-step explanation:

Given the triangles are similar then the ratios of corresponding sided are equal, that is

\frac{CD}{KD} = \frac{CB}{KL} , substitute values

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7 0
3 years ago
Jane wishes to have 20,000 available at the end of 10 years so she deposit money into an account that pays 1.14% compounded mont
max2010maxim [7]

Answer:

\$17,846.12  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=10\ years\\ A=\$20,000\\ r=0.0114\\n=12  

substitute in the formula above  

\$20,000=P(1+\frac{0.0114}{12})^{12*10}  

P=\$20,000/[(1+\frac{0.0114}{12})^{120}]  

P=\$17,846.12  

5 0
3 years ago
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