All categories

3 years ago

Explain why most sports are playing with spherical balls?

2 answers:

8 0

Spherical balls have less friction compared to other type of balls, therefore, it could rolls in many direction
This will make the ball easier to control and made it more enjoyable for the audience to watch

hope this helps

aalyn [17]3 years ago

3 0

Spherical balls are played in most sports because sperical balls have less friction compared to other objects

You might be interested in

What are some ways in which companies can attract and retain employees? (site 2)

slava [35]

The company can offer a variety of benefits not inly for the employee but also for the family.

7 0

3 years ago

Read 2 more answers

12 in.<br> 7 in.<br> 18 in.<br> 25 in.<br> What is the area

emmainna [20.7K]

Answer: 37,800

Step-by-step explanation:

if its a triangle then divide this by 2 and if not then id.k

7 0

3 years ago

The triangles indicated are similar. Solve for x.

sergejj [24]

Hope this helps.................

5 0

3 years ago

Use the graph to determine which statement describes f(x).

Lerok [7]

Answer: B

Step-by-step explanation:

7 0

2 years ago

Please help!!!

Leto [7]

Answer:

- The scientist can use these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

- The scientist can substitute these measurements into $cos\alpha=\frac{adjacent}{hypotenuse}$ and solve for the distance between the Sun and the shooting star (which would be the hypotenuse of the righ triangle).

Step-by-step explanation:

You can observe in the figure attached that "AC" is the distance between the Sun and the shooting star.

Knowing the distance between the Earth and the Sun "y" and the angle x°, the scientist can use only these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

This is:

$cos\alpha=\frac{adjacent}{hypotenuse}$

In this case:

$\alpha=x\°\\\\adjacent=BC=y\\\\hypotenuse=AC$

Therefore, the scientist can substitute these measurements into $cos\alpha=\frac{adjacent}{hypotenuse}$ , and solve for the distance between the Sun and the shooting star "AC":

$cos(x\°)=\frac{y}{AC}$

$AC=\frac{y}{cos(x\°)}$

3 0

3 years ago

Read 2 more answers