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2 years ago

A rectangle has a length of 12 and a width that is half the length. What is the area?

Mathematics

1 answer:

Basile [38]2 years ago

3 0

Answer:

Area = length x width

width = 1/2 length = 12/2 = 6 = width

area = 6x 12 = 72

Hope that answers your question

don't hesitate to comment if you are confused about something

Step-by-step explanation:

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C÷2 when c=26 help me, please

Jobisdone [24]

Answer:

the answer would be 13

Step-by-step explanation:

26/2=13

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3 years ago

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Kevin is 6 years older than Timothy. 4 years ago, Kevin was twice as old as Timothy. Find their present ages.

Novosadov [1.4K]

Step-by-step explanation:

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2 years ago

Rewrite the following the form log (c) log (20) - log (5)

Dmitrij [34]

Answer:log (20/5)

Step-by-step explanation:

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3 years ago

Is the correctx 25<28

trapecia [35]

Answer:

Yes

Step-by-step explanation:

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2 years ago

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A, B, and C are midpoints of ∆XYZ. What is the length of cy

iogann1982 [59]

Answer:

$XY=36\ units$

Step-by-step explanation:

The correct question is

A, B, and C are midpoints of ∆XYZ. What is the length of XY

we know that

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

step 1

Find the length of YZ

$AB=\frac{1}{2}YZ$

we have

$AB=24\ units$

substitute

$24=\frac{1}{2}YZ$

solve for YZ

$YZ=48\ units$

step 2

Find the length of XY

Applying Pythagoras Theorem in the right triangle XYZ

$XZ^2=XY^2+YZ^2$

substitute the given values

$60^2=XY^2+48^2$

solve for XY

$3,600=XY^2+2,304$

$XY^2=3,600-2,304$

$XY^2=1,296$

$XY=36\ units$

Applying the Midpoint Theorem

$BC=\frac{1}{2}XY$ -----> $BC=\frac{1}{2}(36)=18\ units$

$AC=\frac{1}{2}XZ$ -----> $AC=\frac{1}{2}(60)=30\ units$

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2 years ago