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adoni [48]
3 years ago
14

A customer wants you to enlarge a photo to 2 3/4 its current height. The photo’s current height is 3 1/4 inches. What should its

enlarged height be, in inches?
Mathematics
2 answers:
butalik [34]3 years ago
3 0

Answer:

8  15/16 inches

Step-by-step explanation:

Multiply 3  1/4 inches by 2  3/4:

13      11

---- * ----- = 146/16 inches, or 8.9375 inches, or 8  15/16 inches.

 4       4

MAXImum [283]3 years ago
3 0

Answer:  The required enlarged height of the photo is 8\dfrac{15}{16}~\textup{inches}.

Step-by-step explanation:  Given that a customer wants you to enlarge a photo to 2\dfrac{3}{4} its current height and the photo’s current height is 3\dfrac{1}{4} inches.

We are to find the enlarged height of the photo in inches.

The enlarged height of the photo is given by

2\dfrac{3}{4}\times \textup{current height of the photo}\\\\\\=\dfrac{11}{4}\times3\dfrac{1}{4}\\\\\\=\dfrac{11}{4}\times\dfrac{13}{4}\\\\\\=\dfrac{143}{16}\\\\=8\dfrac{15}{16}.

Thus, the required enlarged height of the photo is 8\dfrac{15}{16}~\textup{inches}.

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Answer:

$5.08

Step-by-step explanation:

Step one:

given data

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since the cost of coffee bellow $10 that is $4.80, the 6% fee is applicable

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Step two:

the total fee will be

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= $5.08

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Answer:

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Step-by-step explanation:

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2 years ago
Determine whether The given segments have the same length. Justify your answer
Semenov [28]

We know the distance formula is

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9)

Here A( -4,2) and B(1,4)

So length of AB

= \sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}

Also C(2,1)

Length of BC

= \sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}

So we can see that length of AB is not equal to length of BC

11.

Now AB = \sqrt{29}

Also C(2,-1) & D(4,4)

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<u><em>x < -7</em></u>

<u><em>Step-by-step explanation:</em></u>

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<em><u>simplify</u></em>

<em><u>add 4 to both sides</u></em>

6 0
3 years ago
Read 2 more answers
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