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adoni [48]
3 years ago
14

A customer wants you to enlarge a photo to 2 3/4 its current height. The photo’s current height is 3 1/4 inches. What should its

enlarged height be, in inches?
Mathematics
2 answers:
butalik [34]3 years ago
3 0

Answer:

8  15/16 inches

Step-by-step explanation:

Multiply 3  1/4 inches by 2  3/4:

13      11

---- * ----- = 146/16 inches, or 8.9375 inches, or 8  15/16 inches.

 4       4

MAXImum [283]3 years ago
3 0

Answer:  The required enlarged height of the photo is 8\dfrac{15}{16}~\textup{inches}.

Step-by-step explanation:  Given that a customer wants you to enlarge a photo to 2\dfrac{3}{4} its current height and the photo’s current height is 3\dfrac{1}{4} inches.

We are to find the enlarged height of the photo in inches.

The enlarged height of the photo is given by

2\dfrac{3}{4}\times \textup{current height of the photo}\\\\\\=\dfrac{11}{4}\times3\dfrac{1}{4}\\\\\\=\dfrac{11}{4}\times\dfrac{13}{4}\\\\\\=\dfrac{143}{16}\\\\=8\dfrac{15}{16}.

Thus, the required enlarged height of the photo is 8\dfrac{15}{16}~\textup{inches}.

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Party Palace had 350 balloons that could be purchased. 70 of the balloons were blue. What percent of the balloons were blue? hel
AleksAgata [21]

Answer:

20%

Step-by-step explanation:

70/350 = 0.2  

0.2 x 100 = 20%

5 0
3 years ago
7m+2=6n-5<br> Write a formula for f(m)f(m)f, left parenthesis, m, right parenthesis in terms of mmm.
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Answer: f

(

m

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=

7

m

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6

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
What is the missing length
steposvetlana [31]

Answer:

25 km

Step-by-step explanation:

4 0
3 years ago
Write RS in component form, with R(7, 8) and S(0,5),
german

Answer:

<-7,-3>

Step-by-step explanation:

To write RS in component form we need to know how far to move over horizontally and then how many to move vertically.

Since horizontal movement is the x values, we subtract the x values of R and S first.

0 - 7 = -7

Since vertical movement is in the y values we subtract those next.

5 - 8 = -3

So written in component form we have <-7,-3>

4 0
3 years ago
Read 2 more answers
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