Let the digits of number be x and y
so,
number = 10y + x
given sum of digits = 11
so,
<em>x + y = 11 ...(1)</em>
also,
Reversing its digits decreases the number by 27
so,
reversed number = 10x + y
according to the question,
10x + y - (10y + x) = 27
10x + y - 10y - x = 27
9x - 9y = 27
9(x - y) = 27
<em>x - y = 3. ...(2)</em>
<h3>(1) + (2)</h3>
x + y + x - y = 11 + 3
2x = 14
x = 14/2
x = 7
putting the value of x on (2)
x - y = 3
7 - y = 3
-y = 3 - 7
- y = -4
y = 4
x = 7
so,
number = 10y + x
= 10(4) + 7
= 40 + 7
= 47
<h3>
<em>Required </em><em>number</em><em> </em><em>=</em><em> </em><em>4</em><em>7</em></h3>
<em>hope it helps</em><em> </em><em>!</em>
<em>.</em>
I'm new on this app anyone be my friend