Answer:
Step-by-step explanation:
(x-1)²+(y-2)² =4 compare the given equation with the general one
(x-h)² +(y-k)² =r², where (h, k) are coordinates of the center and r is radius
so center is at ( 1, 2) and radius is 2
Answer:
x= -11
Step-by-step explanation:
36/5 will be simplified 144/20
The domain of the composite function is given as follows:
[–3, 6) ∪ (6, ∞)
<h3>What is the composite function of f(x) and g(x)?</h3>
The composite function of f(x) and g(x) is given as follows:

In this problem, the functions are:
.
The composite function is of the given functions f(x) and g(x) is:

The square root has to be non-negative, hence the restriction relative to the square root is found as follows:


The denominator cannot be zero, hence the restriction relative to the denominator is found as follows:





Hence, from the restrictions above, of functions f(x), g(x) and the composite function, the domain is:
[–3, 6) ∪ (6, ∞)
More can be learned about composite functions at brainly.com/question/13502804
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<span>oh i get it well to make two equations equal you have to find something that fits in x. you see the eqal sign? that is seperating the two equations that you have to make equal </span>