We have a line tangent to the circle with center B at point C. We know that the angle formed between the tangent line at the point of intersection to the line extended from that point to the center of the circle is equal to 90°. In the problem, the 90° is for ∠BCA. We also know that the summation of all angles in a triangle is 180°. We have the solution below for the ∠BAC
180°=∠BAC + ∠BCA + ∠ABC
180°=∠BAC + 90° + 40°
∠BAC =50°
The answer is 50°.
Answer:
(-1,4)
Step-by-step explanation:
Using elimination, add the two equations to get rid of the y variable.
17x = 43 - 15y
+8x = -68 + 15y
=25x = -25
<u>x = -1</u>
Now plug in -1 for x in any of the equations.
17(-1) = 43 - 15y
-17 = 43 - 15y
-60 = -15y
<u>y = 4</u>
Answer:
If there are no variables left, then i guess u just have to write the rest down(constant, coefficient, etc...)
