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denis23 [38]
3 years ago
12

If

x + 5" alt="f(x) = x^{2} + 3x + 5" align="absmiddle" class="latex-formula">, what is f(a +h)?

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
8 0

Answer:

Choice B is correct answer.

Step-by-step explanation:

From question statement , we observe that

A function is given.

f(x) = x²+3x+5

We have to find f(a+h).

f(a+h) = ?

Given function depends on x. We have to find function that depends on a+h.

Putting x = a+h in given function , we have

f(a+h) = (a+h)²+3(a+h)+5(a+h) which is the answer.

Mariulka [41]3 years ago
5 0

Answer:

\large\boxed{C.\ a^2+2ah+h^2+3a+3h+5}

Step-by-step explanation:

f(x)=x^2+3x+5\\\\f(a+h)\to\text{put}\ x=a+h\ \text{to the equation of a function:}\\\\f(a+h)=(a+h)^2+3(a+h)+5\\\\\text{use}\ (a+b)^2=a^2+2ab+b^2\ \text{and the distributive property}\\\\f(a+h)=a^2+2ah+h^2+3a+3h+5

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Which theorem shows that ABC = DEF?*
netineya [11]

Answer:

<h2><em><u>SAS</u></em><em><u> </u></em><em><u>Congruence</u></em><em><u> </u></em><em><u>Theorem</u></em><em><u> </u></em></h2>

Step-by-step explanation:

In ABC. In DEF

AB. = DE. <em>(</em><em>Given</em><em> </em><em>side</em><em>)</em>

<BAC. = <EDF. <em>(</em><em>Given</em><em> </em><em>side</em><em>)</em>

BC. = EF. <em>(</em><em>Given</em><em> </em><em>side</em><em>)</em>

<em><u>Hence</u></em><em><u>,</u></em>

Triangle ABC is congruent to Triangle DEF by<em><u> </u></em><em><u>SAS</u></em><em><u> </u></em><em><u>Congruence</u></em><em><u> </u></em><em><u>Theorem</u></em><em><u>. </u></em>

3 0
3 years ago
How do you simplify 4 over 1/5 I forgot
xeze [42]
4ov [2.718282]r =2.174625orv
5 0
4 years ago
What number is 20% of 40?
VladimirAG [237]

Answer:

It would be 8

Step-by-step explanation:

20% of 40 is 8

6 0
3 years ago
Read 2 more answers
Suppose you are determining the growth rate of two species of plants. Species A is 25 cm tall and grows 3 cm per month. Species
zubka84 [21]

Answer:

b

Step-by-step explanation:

7 0
2 years ago
The product of two integers is eighty,their quotient is five.Write both integers in numerical order and separated by a comma,no
Goryan [66]

SOLUTION

Let the two integers be x and y.

Now, the product of x and y, is 80, that is

\begin{gathered} x\times y=80 \\ xy=80\ldots\ldots\text{.equation 1} \end{gathered}

The quotient of x and y is 5, that is

\begin{gathered} x\div y=5 \\ \frac{x}{y}=5\ldots\ldots\ldots\ldots\text{.}\mathrm{}\text{equation 2} \end{gathered}

From equation 2, make x, the subject, we have

\begin{gathered} \frac{x}{y}=5 \\ \text{cross multiplying } \\ 5\times y=x \\ x=5y \end{gathered}

Now substitute the x for 5y into equation 1, we have

\begin{gathered} xy=80 \\ 5y\times y=80 \\ 5y^2=80 \\ \text{dividing by 5} \\ y^2=\frac{80}{5} \\ y^2=16 \\ \text{take square root of both sides } \\ \sqrt[]{y^2}=\sqrt[]{16} \\ \text{square cancels root} \\ y=4 \end{gathered}

Now substitute y for 4 into any of the equations.

Let us use equation 1 again, we have

\begin{gathered} xy=80 \\ x\times4=80 \\ 4x=80 \\ x=\frac{80}{4} \\ x=20 \end{gathered}

Hence the answer is 4, 20

4 0
1 year ago
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