What would happen if you didn't have chemical energy on the earth

Chemistry

1 answer:

Natalija [7]3 years ago

6 0

We would all DIE and end up DEAD

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Calculate the atomic radius, in nm, of the BCC Metal above utilizing the density and the atomic weight provided by examination b

andre [41]

Answer:

radius = 0.2195 nm

Explanation:

l = 2r

r = 0.439/2 = 0.2195

7 0

3 years ago

Water is unique because the density of its solid, ice,is less than the density of its liquid.How would life be is this is differ

algol13

An object floats if it has low density or has less mass per unit volume. So, Icefloats on water because ICE is lessdenser than WATER. Most of the substances are more dense in their solid state, but water is different. This peculiarity is on account of the structure of ice.

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8 0

4 years ago

Aerobic cellular respiration requires an adequate supply of

Varvara68 [4.7K]

Answer:

oxygen ?

Explanation:

not sure but I think so

3 0

3 years ago

Upon combustion, a 0.8376 g sample of a compound containing only carbon, hydrogen, and oxygen produces 1.6003 gco2 and 0.9827 gh

Wewaii [24]

Answer is: empirical formula for compound is C₂H₆O.
m(CO₂) = 1,6003 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 1,6003 g ÷ 44 g/mol.
n(CO₂) = 0,0364 mol.
n(CO₂) = n(C).
m(C) = 0,0364 mol · 12 g/mol = 0,4368 g.
m(H₂O) = 0,9827 g.
n(H₂O) = 0,9827 g ÷ 18 g/mol.
n(H₂O) = 0,0546 mol.
n(H) = 2 · n(H₂O) = 0,1092 mol.
m(H) = 0,1092 mol · 1 g/mol = 0,1092 g.
m(O) = 0,8376 g - 0,4368 g - 0,1092 g = 0,2916 g.
n(O) = 0,2916 g ÷ 16 g/mol = 0,0182 mol.
n(C) : n(H) : n(O) = 0,0364 mol : 0,1092 mol : 0,0182 mol.
n(C) : n(H) : n(O) = 2 : 6 : 1.

7 0

4 years ago

Draw the best lewis structure for h 2 co 3 and calculate the formal charge on carbon.

schepotkina [342]

The Lewis structure of Carbonic Acid (H₂CO₃) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with hydroxyl groups.

Formal Charge;
Formal charge is caculated as,

Formal charge = # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]

Formal charge on Carbon;

Formal charge = 4 - [ 0 + 8/2]

Formal charge = 4 - [4]

Formal charge = Zero

7 0

3 years ago