Nacl = (. 23+35. 5)
= 58.5g
.
1 mol of Nacl = 58.5g
X mol Of Nacl = 25g
X Mol of Na Cl =25 ÷ 58.5
X mol of Nacl = 0.4 mol
Answer:
2nd
Explanation:
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Answer:
2, Argon PLEASE VOTE 5.0 MARK ME BRAINLIEST AND THANK ME
Explanation:
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The question is incomplete, the complete question is;
Arrange the isotopes of chlorine and sulfur in order of decreasing number of neutrons. Rank the isotopes from most to fewest neutrons. To rank items as equivalent S-33,S-36,S-34,Cl-35,S-32,Cl-37
The isotopes of sulphur arranged in order of decreasing number of neutrons is; S-36, S-34, S-33, S-32. The isotopes of chlorine arranged in order of decreasing number of neutrons is; Cl-37, Cl-35.
Isotopes are atoms of the same element having different mass numbers but the same atomic number.
Isotopes differ in their number of neutrons. The number of neutrons is obtained by subtracting the atomic number of an isotope from its mass number.
The number of neutrons in the isotopes of sulphur are;
S-36 (20 neutrons)
S-34 (18 neutrons)
S-33 (17 neutrons)
S-32 (16 neutrons)
The number of neutrons in the isotopes of chlorine are;
Cl-37 (20 neutrons)
Cl-35 (18 neutrons)
Learn more: brainly.com/question/13214440
<span>this is a limiting reagent problem.
first, balance the equation
4Na+ O2 ---> 2Na2O
use both the mass of Na and mass of O2 to figure out how much possible Na2O you could make.
start with Na and go to grams of Na2O
55.3 gNa x (1molNa/23.0gNa) x (2 molNa2O/4 molNa) x (62.0gNa2O/1molNa2O) = 75.5 gNa2O
do the same with O2
64.3 gO2 x (1 molO2/32.0gO2) x (2 molNa2O/1 mol O2) x (62.0gNa2O/1molNa2O) = 249.2 g Na2O
now you must pick the least amount of Na2O for the one that you actually get in the reaction. This is because you have to have both reacts still present for a reaction to occur. So after the Na runs out when it makes 75.5 gNa2O with O2, the reaction stops.
So, the mass of sodium oxide is
75.5 g</span>
