An urn contains eight blue balls and seven yellow balls. if six balls are selected randomly without being replaced, what is the
probability that of the balls selected, two of them will be blue and four of them will be yellow
1 answer:
to be sure that 2 of them will be blue i have to select 7+2=9 balls
7+8=15 balls in the urn
P=9/15
to be sure that 4 of them will be yellow i have to select 8+4=12 balls
P=12/15
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