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Minchanka [31]
2 years ago
14

An urn contains eight blue balls and seven yellow balls. if six balls are selected randomly without being​ replaced, what is the

probability that of the balls​ selected, two of them will be blue and four of them will be​ yellow
Mathematics
1 answer:
Vlad1618 [11]2 years ago
8 0

to be sure that 2 of them will be blue i have to select 7+2=9 balls
7+8=15 balls in the urn
P=9/15

to be sure that 4 of them will be yellow i have to select 8+4=12 balls
P=12/15


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Then the original price was $42

Because it is half off we multiply 21 by 2 and get 42.

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4. What are the values of x and y? HELP PLEASE
Sergeeva-Olga [200]
The bottom answer is correct. I had some trouble with this so I had to find x and y in separate parts.

TO FIND X
notice that the top triangle and bottom triangles are similar, meaning if you multiple all three sides of one by a specific number, it becomes the same size as the bottom triangle.

17 x n = 8, therefore n=8/17
8 x n = X, therefore X=64/17

For some reason, this does not give a correct value for Y, so I had to use trig 

TO FIND Y 

Notice that the angle DAB is the same as DBC (lets call this angle Ø)

Using trig rule, we know that the cos of an angle is equal to the adjacent side divided by the hypotenuses.

We can now form some equations:

cosØ = 15/17 (from the top triangle)
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2 years ago
find the value of the variable. if your answer is not an interger, leave it in simplest radical form.
kotykmax [81]

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A

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using the sine ratio in the right triangle, then

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Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

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First, let find k. Substitute p= 200

q= 2, and r=3.

\frac{200}{2(3) {}^{2} }  = k

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p =  \frac{2000}{9}

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