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GrogVix [38]
4 years ago
5

What is the average velocity between 12.00 and 15.00 seconds

Mathematics
2 answers:
Vedmedyk [2.9K]4 years ago
6 0
The answer is 13.50 seconds. You just add both numbers and divide them by two then you will get the average.
bekas [8.4K]4 years ago
3 0

The average between 12.00 and 15.00 seconds
can be defined in a few different ways.

Way #1:  (speed)

     Average speed =
         (1/2) (the speed at 12 seconds  +  the speed at 15 seconds) .


Way #2:  (speed)

   Average speed =
       (1/3) (the distance covered between 12.00 and 15.00 seconds)


Way #3:  (velocity)

   Average velocity =
     (1/3) (distance between location at 12 sec and location at 15 sec)
       in the direction from location at 12 sec to location at 15 sec.


That's the best we can do with the combination of given and
not given information in the question.

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Kurt baked 9 batches of cookies. Each batch contained 9 cookies. How many cookies did Kurt bake?
soldi70 [24.7K]
9*9=81. So Kurt baked 81 cookies.
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You open a savings account with a beginning balance of $600. You plan on depositing $50 every month until you have enough money
telo118 [61]

Answer:

48 months

Step-by-step explanation:

first take how much you need and add how much you want to leave, so 2500+500=3000. Then delete 600 from 3000, which will give you $2400. divide $2400 by 50 which gives you 48. it will take 48 months to get enough money to purchase a car at $2500 and leave $500 in the account.

8 0
3 years ago
Ok last question plz help me with the question for this topic dont wanna get it wrong
Crank

For this problem plug in the given x and y values:

For the first one: No

second one: No

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fourth one: No

7 0
4 years ago
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Students are making finger puppets for a puppet show.
zvonat [6]

Answer:

Its 3

Step-by-step explanation:

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7 0
3 years ago
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Given right triangle GYK, what is the value of tan(G)?
Ludmilka [50]

<u>Answer:</u>

The value of tan(G) in the  right triangle GYK Is \sqrt{3}

<u>Step-by-step explanation:</u>

Given

Measure of angle at G=60^{\circ}

Measure of angle at Y=30^{\circ}

Measure of angle at K=90^{\circ}

To find:

\tan (G)=?

Solution:

In trigonometry we know that

\tan G=\frac{\sin G}{\cos G}

G=60^{\circ}

So,

\sin (60)=\frac{\sqrt{3}}{2}

\cos (60)=\frac{1}{2}

Substituting in the formula we have,

\tan G=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}

\tan G=\frac{\sqrt{3}}{2} \times \frac{2}{1}

\tan G=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}

\tan G=\sqrt{3}

Result:

Thus the value of \tan G=\sqrt{3}

8 0
3 years ago
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