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Olegator [25]
4 years ago
7

Which groups on the periodic table contain metalloids?​

Mathematics
2 answers:
natali 33 [55]4 years ago
7 0

Answer:

Group 13 to group 16

Step-by-step explanation:

Nikolay [14]4 years ago
3 0

Answer: C

Step-by-step explanation:

The answer for K12

took the test

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Michelle works at a beauty salon. last month she received an average tip of $9 from her 88 clients. what was her tip income for
mars1129 [50]

Answer:

answer is 792

Step-by-step explanation:

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4 0
3 years ago
If f(x)=2x+7 and g(x)= x^2-4/2x+1 then g(f(-5))?<br><br>a)-3<br>b)6<br>c)-1<br>d)2​
AURORKA [14]

Answer:

It should be 2

Step-by-step explanation:

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5 0
3 years ago
Landon is building new bookshelves for his bookstore new mystery section each shelf can hold 34 books there are 1,265 mystery bo
Brilliant_brown [7]
1265/34=37.2
Since the number of shelves needs to be integer number, so he needs 38 shelves.
4 0
3 years ago
No spam or leaks
g100num [7]

The slope of the line representing the linear graph is a rate of 3.2 meters per second.

<h3 /><h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the slope of the line and m is the y intercept.

Let y represent the distance in meters and x represent the time in seconds. Hence:

  • Using the points (20, 64) and (60, 192)

Slope = \frac{y_2-y_1}{x_2-x_1} =\frac{192-64}{60-20} =3.2

The slope of the line representing the linear graph is a rate of 3.2 meters per second.

Find out more on linear equation at: brainly.com/question/14323743

5 0
3 years ago
A cellphone provider has the business objective of wanting to estimate the proportion of subscribers who would upgrade to a new
stiv31 [10]

Answer:

z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913  

p_v =P(z>3.913)=0.000046  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=135 represent the subscribers that would upgrade to a new cellphone at a reduced cost

\hat p=\frac{135}{500}=0.27 estimated proportion of subscribers that would upgrade to a new cellphone at a reduced cost

p_o=0.2 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportion is higher than 0.2 or not.:  

Null hypothesis:p \leq 0.2  

Alternative hypothesis:p > 0.2  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.913)=0.000046  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

6 0
4 years ago
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