That is when h=0
so assuming yo meant
h(t)=-16t²+24t+16
solve for t such that h(t)=0
because when height=0, the gymnast hits the ground
so
0=-16t²+24t+16
using math (imma complete the square
0=-16(t²-3/2t)+16
0=-16(t²-3/2t+9/16-9/16)+16
0=-16((t-3/4)²-9/16)+16
0=-16(t-3/4)²+9+16
0=-16(t-3/4)²+25
-25=-16(t-3/4)²
25/16=(t-3/4)²
sqrt both sides
+/-5/4=t-3/4
3/4+/-5/4=t
if we do plus (because minus would give us negative height)
8/4=t
2=t
it takes 2 seconds
I think it would be 3.19.
Dividing 25.52 by 8.
50:
40 is 10 less than 50
60 is 10 more than 50
You’re given g(x) = x^2 - 5
When asked to find g(9), you’re being told that x=9, since the x in the g(x) was replaced by 9.
So that’s telling you to put 9 in for all x’s:
g(9) = (9)^2 - 5
You then just need to clear up the right hand side.
9^2 - 5 = 81 - 5
= 76
So, g(9) = 76
