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Karolina [17]
3 years ago
9

If one side of a square 2x-1 in, what is the perimeter in terms of x

Mathematics
1 answer:
Vesnalui [34]3 years ago
5 0
(2x-1)×4=8x-4
I hope it helps ;)
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Find the height of a triangle with a base of 4 1/4 cm and an area of 5 5/16 cm squared
Paha777 [63]

Answer:

hb=2.5

Step-by-step explanation:

base = 4

area  =  5

6 0
3 years ago
In a game, Janeesa started with 0 points. She then earned 50 points, lost 80 points and earned 10 points. Which number line show
umka2103 [35]

Answer:

-20

Step-by-step explanation:

If Jeneesa started with, 0 points and she earned 50, then she would have 50. If she lost 80 points, she would go into the negatives. She would be at -30, and when she earned 10 more points, she would be at -20.

I don't know what your options look like, but look at the one(s) with -20 at the end and figure out what one best fits my explanation (and the numbers I use)!

3 0
3 years ago
I need help i need to get this right please i begggggg you<br>i need help ASAP
Flauer [41]
Please say brainliest.

The answer is yes.

Plug 4 in for the value of n so you have 4+8 is less than it equal to 13. And since 12 is less than 13 it is true, and a solution to the inequality.
4 0
3 years ago
What is the value of the function at x = - 2 a y= -2 b y = 0 c y= 2 d y= 3
Ahat [919]

Answer:

C

Step-by-step explanation:

To find the value of the function at x = - 2

Locate x = - 2 on the x- axis then go up vertically until the line is met.

The read the corresponding value of y from the y- axis

x = - 2 ⇒ y = 2 → C

6 0
3 years ago
A bag of chocolate mix weighed 1/4 of a kilogram could make enough brownies to feed 1/7 of the students at school how many bags
Hoochie [10]
A "whole" will be 7/7, or just 1 whole.

so we know one bag can do 1/7 of all students, how many will it be needed to do 7/7?

well, in 7/7 there are seven 7/7, so, 7 bags then, or one could say,

\bf \begin{array}{ccll}&#10;\stackrel{chocolate}{bag}&\stackrel{fraction}{students}\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;1&\frac{1}{7}\\\\&#10;x&\frac{7}{7}&#10;\end{array}\implies \cfrac{1}{x}=\cfrac{\quad \frac{1}{7}\quad }{\frac{7}{7}}\implies \cfrac{1}{x}=\cfrac{1}{7}\cdot \cfrac{7}{7}&#10;\\\\\\&#10;\cfrac{1}{x}=\cfrac{1}{7}\implies 7=x
5 0
2 years ago
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