All categories

3 years ago

If one side of a square 2x-1 in, what is the perimeter in terms of x

Mathematics

1 answer:

Vesnalui [34]3 years ago

5 0

(2x-1)×4=8x-4
I hope it helps ;)

You might be interested in

John works two jobs. He earns $10 an hour babysitting his neighbor's children and $15 an hour mowing lawns in his neighborhood.

Jlenok [28]

Add up all the numbers

7 0

2 years ago

What is the measure of c? a = 15 j = 24 k = 32

inessss [21]

Answer:

The answer to your question is c = 20

Step-by-step explanation:

Data

a = 15

j = 24

k = 32

c = ?

Process

Use proportions to solve this problem. Compare the small triangle and the large triangle.

1.- Proportion of the small triangle

c/15

2.- Proportion of the large triangle

k/j

3.- Equal but terms and solve for c

c/15 = k/j

-Substitution

c / 15 = 32/24

c = 32(15)/24

-Result

c = 20

4 0

3 years ago

HELPPPP PLEASEEE!!! I NEED HELPP

zhenek [66]

Answer:

≥≤ are used when the number is less/greater or equal than some thing.

>< are used when a number is strictly less/greater than some thing.

1) a number x is less than 0 or at least 3

A number x is less than 0 is written as: x < 0.

x is at least 3 is written as: x ≥ 3.

Then we can write the statement as:

x < 0 ∨ x ≥ 3.

where ∨ means "or"

2) a number x is less than or equal to 4 and greater than -1

x less than or equal to 4 is written as: x ≤ 4

x is greater than -1 is written as: x > - 1.

We can write the statement as:

-1 < x ≤ 4

3) a number x is less than 8 and greater than or equal to 5

x is less than 8 is written as: x < 8

x is greater than or equal to 5 is written as: x ≥ 5.

Then the statement can be written as:

5 ≤ x < 8,

6 0

3 years ago

The incline of a roller coaster is 2 times as long as its elevation, and the horizontal length of the roller coaster is 11 m mor

Gelneren [198K]

Let
x-------> the horizontal length of the roller coaster
y------> the elevation of the roller coaster
c------> the incline of a roller coaster

we know that
applying the Pythagoras theorem
c²=x²+y²-----> equation 1
c=2y-----> equation 2
x=11+y----> equation 3

substitute equation 2 and equation 3 in equation 1
[2y]²=(11+y)²+y²
4y²=11²+22y+y²+y²
2y²-22y-121=0

using a graph tool-----> to resolve the second order equation
see the attached figure

the solution is
y=15.026 m

c=2*y-----> c=2*15.026----> c=30.052 m

the answer is
30.05 m

7 0

3 years ago

If f(x) = 2x−5, then what is the value of f(2) + f(5)

DochEvi [55]

First of all f(2)=2(2)-5=-1 and f(5)=2(5)-5=5
so
f(2)+f(3)=-1+5=4

7 0

3 years ago