Question

Solve the simultaneous equations 2x – 3y = 12 3x + 4y = 1

Answer 1

Answer:

x=3 and y=−2

Step-by-step explanation:

Multiply the first equation by 4,and multiply the second equation by 3.

4(2x−3y=12)

3(3x+4y=1)

Becomes:

8x−12y=48

9x+12y=3

Add these equations to eliminate y:

17x=51

Then solve17x=51for x:

17x=51

17x

17

=

51

17

(Divide both sides by 17)

x=3

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

2x−3y=12

Substitute3forxin2x−3y=12:

(2)(3)−3y=12

−3y+6=12(Simplify both sides of the equation)

−3y+6+−6=12+−6(Add -6 to both sides)

−3y=6

−3y

−3

=

6

−3

(Divide both sides by -3)

y=−2

Answer 2

Answer:

$(3,-2)$

Step-by-step explanation:

$2x-3y=12$

$2(3)-3(-2)=12$

$6--6=12$        Two negative signs together makes a addition

$3x+4y=1$

$3(3)+4(-2)=1$

$9-8=1$