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True [87]
3 years ago
7

Factor the following polynomial completely. -x 2 y 2 + x 4 + 4y 2 - 4x 2

Mathematics
2 answers:
zlopas [31]3 years ago
5 0

Answer:

(x + y)(x - y) (x + 2)(x - 2)

Step-by-step explanation:

-x^2 y^2 + x^4 + 4y^2 - 4x^2

Lets rearrange the terms

x^4 -x^2 y^2 - 4x^2 + 4y^2

Then we group first two terms and last two terms

(x^4 -x^2 y^2)+(- 4x^2 + 4y^2)

Factor out each group

x^2(x^2 - y^2) - 4 (x^2 - y^2)

(x^2 - y^2)(x^2 - 4)

Apply formula a^2 - b^2 = (a+b)(a-b)

(x + y)(x - y) (x + 2)(x - 2)

fgiga [73]3 years ago
3 0
<span>-x^2 y^2 + x^4 + 4y^2 - 4x^2
= </span>x^4 -x^2 y^2 - 4x^2 + 4y^2<span>
= x^2 (x^2 - y^2) - 4 (x^2 - y^2)
= (x^2 - y^2)(x^2 - 4)
= (x + y)(x - y) (x + 2)(x - 2) (....using a^2 - b^2 = (a+b)(a-b) )

hope it helps</span>
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