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2 years ago

10

PLEASE HELP ME OUT IM STUCK

1 answer:

Taya2010 [7]2 years ago

5 0

Answer:

The volume is 160 inches

Step-by-step explanation:

If u search in googl volume of pyramid and add in the lengths it will give u the answer!

the formula is lwh/3

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satela [25.4K]

Answer:

$\large\boxed{2a+14}$

Step-by-step explanation:

$4(a + 2 ) - 2 (a - 3)\qquad\text{use distributive property:}\ a(b+c)=ab+ac\\\\=4a+8-2a-(-6)\qquad\text{combine like terms}\\\\=(4a-2a)+(8+6)\\\\=2a+14$

5 0

3 years ago

Round this number to the nearest tenth.<br><br> 52.85

k0ka [10]

Answer:

52.9

numbers 0-4 the number stays the same

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6 0

3 years ago

1 1/4 divided by 2/3

Ksju [112]

Answer:

1.875

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru

jenyasd209 [6]

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time ( $t_{T}$ ) that Keenan will be from home is the sum of run ( $t_{R}$ ), hang out ( $t_{H}$ ) and walk times ( $t_{W}$ ), measured in hours:

$t_{T} = t_{R}+t_{H}+t_{W}$

If Keenan runs and walks at constant speed, then equation above can be expanded:

$t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}$

Where:

$x_{R}$ , $x_{W}$ - Run and walk distances, measured in miles.

$v_{R}$ , $v_{W}$ - Run and walk speeds, measured in miles per hour.

Given that $x_{R}=x_{W} = 2.5\,mi$ , $v_{R} = 6\,\frac{mi}{h}$ , $v_{W} = 4\,\frac{mi}{h}$ and $t_{H} = 0.75\,h$ , the total time is:

$t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }$

$t_{T} = 1.792\,h$ ( $1\,h\,48\,m$ )

Kennan will be from home approximately an hour and 48 minutes.

7 0

3 years ago

WHATS THE ANSWER ILL GIVE BRAINLIEST.

Gemiola [76]

A I’m pretty sure!!!

8 0

3 years ago