1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lorico [155]
2 years ago
11

PLEASE HELP QUICKLY!!!

Mathematics
1 answer:
kirill115 [55]2 years ago
5 0

Answer:

sunday

Step-by-step explanation:

i dont want brainliest give it to the other guy

You might be interested in
arts academy requires there to be 6 teachers for every 144 students and 3 tutors for every 24 students. How many students does t
jonny [76]

Answer:

the teachers would have 24 students per teacher. 10 students per tutor. There would need to be 11 tutors

Step-by-step explanation:

each tutor would have 10 students then if you do 11 times 10 you get 11

(hope this helps can I pls have brainlist (crown)☺️)

4 0
2 years ago
Comparing the two ratios 2/4 and 1/2<br> 2/4 is larger
kumpel [21]

Answer:

<em><u>3.5 : 7 > 1.2 : 2.5.</u></em>

Step-by-step explanation:

1. Compare the ratios 4 : 5 and 2 : 3.

Solution:

Express the given ratios as fraction

4 : 5 = 4/5 and 2 : 3 =2/3

Now find the L.C.M (least common multiple) of 5 and 3

The L.C.M (least common multiple) of 5 and 3 is 15.

Making the denominator of each fraction equal to 15, we have

4/5 = (4 ×3)/(5 ×3) = 12/15 and 2/3 = (2 ×5)/(3 ×5) = 10/15

Clearly, 12 > 10

Now, 12/15 > 10/15

Therefore, 4 : 5 > 2 : 3.

2. Compare the ratios 5 : 6 and 7 : 9.

Solution:

Express the given ratios as fraction

5 : 6 = 5/6 and 7 : 9 =7/9

Now find the L.C.M (least common multiple) of 6 and 9

The L.C.M (least common multiple) of 6 and 9 is 18.

Making the denominator of each fraction equal to 18, we have

5/6 = (5 ×3)/(6 ×3) = 15/18 and 7/9 = (7 ×2)/(9 ×2) = 14/18

Clearly, 15 > 14

Now, 15/18 > 14/18

Therefore, 5 : 6 > 7 : 9.

3. Compare the ratios 1.2 : 2.5 and 3.5 : 7.

Solution:

1.2 : 2.5 = 1.2/2.5 and 3.5 : 7 =3.5/7

1.2/2.5 = (1.2 ×10)/(2.5 ×10 ) = 12/25 and 3.5/7 = (3.5 ×10)/(7 ×10) = 35/70 = 1/2

[We removed the decimal point from the ratios now, we will compare the ratio]

Now find the L.C.M (least common multiple) of 25 and 2

The L.C.M (least common multiple) of 25 and 2 is 50.

Making the denominator of each fraction equal to 50, we have

= 12/25 = (12 ×2)/(25 ×2) = 24/50 and 1/2 = (1 ×25)/(2 ×25) = 25/50

Now, 25/50 > 24/50

Therefore, 3.5 : 7 > 1.2 : 2.5.

4 0
2 years ago
X+y = -15 in y = mx+b form
gayaneshka [121]

Answer:

y=-15x+b

Step-by-step explanation:

Just move it around and use a calucator

8 0
2 years ago
The graph of the function g(x) is a transformation of the parent function f(x)=x².
Len [333]

Answer:

The answer is c)

Step-by-step explanation:

g(x)=x^2-4

3 0
3 years ago
The side of a square is Two raised to the seven halves power inches. Using the area formula A = s2, determine the area of the sq
AlladinOne [14]

Answer:

Step-by-step explanation:

Area of a square = s²

s is the side length of the square

Given

s = 2^{7 1/2}

s = 2^15/2

Area = ( 2^15/2)²

Area = 2^15

Hence two area of the square is 2^15 inches

4 0
2 years ago
Read 2 more answers
Other questions:
  • A college student takes out a $7,500 loan from a bank. What will the balance of the loan be after one year (assuming the student
    11·1 answer
  • Divide. (20x^3-35x+18)/(5x-5)
    5·1 answer
  • Math help? <br> If you have an eight foot ramp ...
    5·2 answers
  • Round 35.113 to the nearest hundredth
    5·1 answer
  • Find the values of x in the isosceles triangle
    7·1 answer
  • What is the range of the function y=2x+1 for the domain 2&lt;=x&lt;=5?
    12·1 answer
  • 5x + 9 = x - 23 find X​
    7·1 answer
  • What’s the hypotenuse?
    9·1 answer
  • Choose the equation and the slope of the line that passes trough (5,-3) and is parallel to the x-axis
    7·1 answer
  • What is f(g(x)) if f(x)= 4x²+3x-4 and g(x)=2x​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!