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alexdok [17]
3 years ago
5

~PLEASE HELP OFFERING 15 POINTS~

Mathematics
2 answers:
raketka [301]3 years ago
4 0
Correct answer is D).
A) and C) are polynomials, so x∈R, in B) we have √x, and in this case x ≥ 0.
Sergio [31]3 years ago
3 0

Answer:

f(x)=\frac{1}{x-3}

Step-by-step explanation:

find function that consist of domain = all real numbers greater than 3

A) f(x) = 3x

f(x) is a linear function, for all linear function the domain is set of all real numbers.

B)  f(x)= \sqrt{x}

For square root function , the domain is set of all real numbers greater than 0

C) f(x) = 3x + 4

 f(x) is a linear function, for all linear function the domain is set of all real numbers.

D)  f(x)=\frac{1}{x-3}

for square root function we set x-3>0 and solve for x

x > 3, so domain is all real numbers greater than 3

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ElenaW [278]

Answer:

f(x)=x^3 +4x^2 +16x +64

Step by step explanation:

\text{Given that,  two roots are}~ -4~ \text{and}~  4i.\\\\\text{Let,}\\\\~~~~~~~x = 4i\\\\\implies  x^2 = 16i^2~~~~~~~;[\text{Square on both sides}]\\\\\implies x^2 = -16~~~~~~~~;[i^2 = -1]\\\\\implies x^2 +16 = 0\\\\\text{So,}~ x^2 +16~ \text{ is a factor of the 3 degree polynomial}.\\ \\ \text{The polynomial is ,}\\\\ f(x) = (x+4)(x^2 +16)\\\\~~~~~~~=x^3 +16x +4x^2 +64\\\\~~~~~~~=x^3 +4x^2 +16x +64

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5 0
3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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