The answer would be false.
Since the figure above is a square, that would mean all sides are equal size. If x=5, that would make segment AD bigger than segment BC.
Circumference = 2 x pi x radius
27 in = 2 x 3.14 x radius
Solve for the radius
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There are 5 ways to test if two figures are congruent, namely;
side-angle-side(SAS)
Angle-side-angle (ASA)
Angle-angle-side(AAS)
Hypotenuse-leg (HL)
3 Sides (SSS)
here we shall focus on SSS. When the three corresponding sides of 2 figures say a triangle have the same length we will conclude that the triangles are congruent by SSS.
Therefore from our choices we can conclude that triangles ABC and ADC are only congruent if the two other side have the same length and BC=DC.
The answer is yes;
B] Yes, but only if BC=DC
Answer:
Step-by-step explanation:
A) 5x - 7 = 5x becomes -7 = 0 if 5x is subtracted from both sides. This result is never true, so NO SOLUTION
B)3x−9=3(x−3) Performing the indicated multiplication, we get
3x - 9 = 3x - 9. This is always true, so there are INFINITELY MANY SOLUTIONS
C)2x−6=−2(x−3) Performing the indicated multiplication, we get
2x - 6 = -2x + 6. Adding 2x - 6 to both sides results in
4x - 12 = 0, or 4x = 12. Thus, the solution is x = 3. ONE SOLUTION
D)2x+6−5x=−3(x This equation is incomplete
