All categories

3 years ago

Need some help please

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

6 0

Answer:

84 is the median

Step-by-step explanation:

100, 100, 92, 90, 88, 84, 81, 80, 80, 75, 40

\ 100, 92, 90, 88, 84, 81, 80, 80, 75 /

\ 92, 90, 88, 84, 81, 80, 80 /

\ 90, 88, 84, 81, 80 /

\ 88, 84, 81 /

\ __ /

denis23 [38]3 years ago

5 0

The median of this problem is 84

You might be interested in

4-9x= -14 solve the inequality.

polet [3.4K]

4 - 9x = -14
4 - 4 - 9x = -14 - 4
9/9x = -18/9
x = -2

6 0

3 years ago

{{{{{PLEASE HELP ASAP}}}}

4vir4ik [10]

Answer:

126

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Convert 6500 ounces to liters. plz show work

yuradex [85]

Answer:

About 192.22775 liters

Step-by-step explanation:

1 ounce = 0.0295735 litre

=> 6500 ounces = 0.0295735 x 6500 = 192.22775 litres

7 0

3 years ago

What is 21000 rounded to the nearest ten thousand

denpristay [2]

A number rounded to the nearest 10000, means that the last four digits of that number (on the left of the decimal point) are 0.
<span>However, if the fourth-last digit to the left of the decimal point is 5 or greater, the number to the left of that is rounded to 1 number higher. For example, if you were rounding 145293 to the nearest 10000, it would be 150000.

However, the </span>fourth-last digit to the left of the decimal point in this case is 1.
Therefore, <span> 21000 rounded to the nearest 10000 is 20000.

</span>

4 0

3 years ago

Read 2 more answers

One variable examined is the survival rate 10 years after tagging. The scientists observed that 10 of the 50 metal tagged pengui

Oksana_A [137]

Answer: 90% confidence interval would be $(-0.2483,-0.0717)$

Step-by-step explanation:

Since we have given that

n₁ = 50

Number of metal tagged penguins survived = 10

So, $p_m=\dfrac{10}{50}=0.2$

n₂ = 50

Number of electronic tagged penguins = 18

So, $p_e=\dfrac{18}{50}=0.36$

So, at 90% confidence interval, z = 1.28

So, interval would be

$(p_m-p_e)\pm z\sqrt{\dfrac{p_m(1-p_m)}{n}+\dfrac{p_e(1-p_e)}{n}}\\\\=(0.2-0.36)\pm 1.28\sqrt{\dfrac{0.2\times 0.8}{50}+\dfrac{0.36\times 0.64}{50}}\\\\=-0.16\pm 0.0883\\\\=(-0.16-0.0883,-0.16+0.0883)\\\\=(-0.2483,-0.0717)$

Hence, 90% confidence interval would be

$(-0.2483,-0.0717)$

6 0

3 years ago