In the equation of a straight line (when the equation is written as "y = mx + b"), the slope is the number "m" that is multiplied on the x, and "b" is the y-intercept (that is, the point where the line crosses the vertical y-axis)

3 0

3 years ago

Write the equation of the ellipse with foci at (-2,2) and (4,2) and major axis of length 10 *

Luda [366]

Answer:

The answer to your question is $\frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1$

Step-by-step explanation:

Data

Foci (-2, 2) (4, 2)

Major axis = 10

Process

1.- Plot the foci to determine if the ellipse is vertical or horizontal. See the picture below.

From the graph we conclude that it is a horizontal ellipse.

2.- Determine the foci axis (distance between the foci)

2c = 6

c = 6/2

c = 3

3.- Determine a

2a = 10

a = 10/2

a = 5

4.- Determine b using the Pythagorean theorem

a² = b² + c²

-Solve for b

b² = a² - c²

b² = 5² - 3²

b² = 25 - 9

b² = 16

b = 4

5.- Find the center (1, 2) From the graph, it is in the middle of the foci

6.- Find the equation of the ellipse

$\frac{(x - 1)^{2}}{5^{2}} + \frac{(y - 2)^{2}}{4^{2}} = 1$

$\frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1$

3 0

2 years ago

What is the angle in part c? Thank you.

Anton [14]

It looks like an equilateral triangle if I am correct then angle C equals 60 degrees

7 0

3 years ago