Answer:
r = I/P*t
Step-by-step explanation:
So I dont know how to explain it but to show you how to do it.
I = Prt
Divide both sides by Pt to get r alone

Therefore your answer is r = I/P*t
Hopes this help :)
Y = 0:

0 is neither prime nor composite.
y=1:

3 is a prime number (because only 3 and 1 divide evenly into it)
y = 2:

8 is a composite number (because multiple different numbers divide evenly into it: 1, 2, 4, and 8)
Answer:
x=3, y=8; (3,8)
Step-by-step explanation:
To use the substitution method, first solve for a variable.
2x+y=14
2x+y(-2x)=14(-2x)
y=14-2x
Now substitute y in the other equation with 14-2x
5x-2(14-2x)= - 1
Simplify by multiplying inside the parenthesis.
5x-28+4x= - 1
Combine the x values
9x-28= - 1
9x=27
x=3
Now substitute the x value in to solve for y
2(3)+y=14
6+y=14
y=8
Answer:
34. A negative number multiplied by a positive number will always have a negative product. The right answer should be -8.14.
35. When dividing fractions, you have to use the same-change-flip rule. The work should be like this: -1/4 x 2/3 = -2/12 = -1/6. The correct answer is -1/6.
36. In this problem, you need to convert 2 1/5 into a decimal, then multiply by -30. (2.2 x -30) The answer is -66 degrees.
So the rule with multiplying exponents of the same base is
. Apply this rule here:

Next, the rule with converting negative exponents into positive ones is
. Apply this rule here:

<u>Your final answer is 1/49.</u>
<h2>------------------------------------------------</h2>
So an additional rule when it comes to exponents is ![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=%20x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D%20)
In this case, your fractional exponent, x^9/7, would be converted to
. However, I had just realized you can further expand this.
Remember the rule I had mentioned earlier about multiplying exponents of the same base? Well, you can apply it here:
![\sqrt[7]{x^9}=\sqrt[7]{x^7*x^2}=x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7Bx%5E9%7D%3D%5Csqrt%5B7%5D%7Bx%5E7%2Ax%5E2%7D%3Dx%5Csqrt%5B7%5D%7Bx%5E2%7D%20)
Your final answer would be ![x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=%20x%5Csqrt%5B7%5D%7Bx%5E2%7D%20)