Question

Write the point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8. include all your work in your answer.

Answer 1

Answer:

The point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8 is 8x + y + 62 = 0

Solution:

The point slope form of the line that passes through the points $\left(x_{1} y_{1}\right)$ and parallel to the line with slope “m” is given as  

$y-y_{1}=m\left(x-x_{1}\right)$ --- eqn 1

Where “m” is the slope of the line.  

$x_{1} \text { and } y_{1}$ are the points that passes through the line.

From question, given that slope “m” = -8

Given that the line passes through the points (-8,2).Hence we get

$x_{1}=-8 ; y_{1}=2$

By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -8 can be found out.

y-2=-8(x-(-8))

On simplifying we get

y – 2 = -8(x +8)

y – 2 = -8x -64

y – 2 +8x +64 = 0

8x + y +62 = 0

Hence the point slope form of given line is 8x + y +62 = 0