V=basearea times 1/3 times height
basearea=6<span>4π m2
hmm, they try to make it difficult
basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9
h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20
v=1/3*64pi*20=1280pi/3 m^3=1350.4
C
</span>
Answer:
55.32% probability that a late package was delivered by express delivery service 2
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Late delivery.
Event B: Service 2 was used.
A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery service 2.
100 - 35 = 65%.
So 
Service 2 has a record of 2.0% of packages being delivered late.
This means that 
Probability of a late delivery.
35% from service 1. Of those, 3% are late.
65% from service 2. Of those, 2% are late.
So

What is the probability that a late package was delivered by express delivery service 2
55.32% probability that a late package was delivered by express delivery service 2