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3 years ago

Really need to know this for math!

Mathematics

1 answer:

Len [333]3 years ago

6 0

Answer:

I had to look up the problem B4 because your image doesn't show the rest of the information

B4 = 12

B5 = 1,738

Step-by-step explanation:

if you need help on any other questions on this, i can't see them in the image

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8th grade math question need answer asap

o-na [289]

P = 16 because if u add 4 to 14 you will get 18 and minus 2 from it to get 16

5 0

3 years ago

9471.3569 rounded to the hundred place

nadya68 [22]

Since the hundred place is the 4 and the tens place is higher than 5 ( it is 7) to round to the hundreds place it would be 9500

6 0

3 years ago

Write a division problem that will have a 2 digit quotient and another division problem that will have a 3 digit quotient. Expla

o-na [289]

Answer:

$\frac{240}{4} =60$

$\frac{1800}{3} =600$

Step-by-step explanation:

1. The result should by a 2 digit number.

So, I fix a two digit number first, say 60.

Then, I multiplied it by some random integer, say 4 and got 240.

Now, 240 is my dividend and 4 is my divisor.

My division problem is:

$\frac{240}{4} =60$

2. The result should be a 3 digit number.

So, I fix a three digit number first, say 600.

Then, I multiplied it by some random integer, say 3 and got 1800.

Now, 1800 is my dividend and 3 is my divisor.

My division problem is:

$\frac{1800}{3} =600$

6 0

3 years ago

Read 2 more answers

A fried chicken franchise finds that the demand equation for its new roast chicken product, "Roasted Rooster," is given by p = 4

LUCKY_DIMON [66]

Answer:

1. $q=(\dfrac{45}{p})^{\frac{2}{3}}$

2. $E_d=-\dfrac{2}{3}$

Step-by-step explanation:

The given demand equation is

$p=\dfrac{45}{q^{1.5}}$

where p is the price (in dollars) per quarter-chicken serving and q is the number of quarter-chicken servings that can be sold per hour at this price.

Part 1 :

We need to Express q as a function of p.

The given equation can be rewritten as

$q^{1.5}=\dfrac{45}{p}$

Using the properties of exponent, we get

$q=(\dfrac{45}{p})^{\frac{1}{1.5}}$ $[\because x^n=a\Rightarrow x=a^{\frac{1}{n}}]$

$q=(\dfrac{45}{p})^{\frac{2}{3}}$

Therefore, the required equation is $q=(\dfrac{45}{p})^{\frac{2}{3}}$ .

Part 2 :

$q=(45)^{\frac{2}{3}}p^{-\frac{2}{3}}$

Differentiate q with respect to p.

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{2}{3}-1}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{5}{3}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})$

Formula for price elasticity of demand is

$E_d=\dfrac{dq}{dp}\times \dfrac{p}{q}$

$E_d=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{(45)^{\frac{2}{3}}p^{-\frac{2}{3}}}$

Cancel out common factors.

$E_d=(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{p^{-\frac{2}{3}}}$

Using the properties of exponents we get

$E_d=-\dfrac{2}{3}(p^{-\frac{5}{3}+1-(-\frac{2}{3})})$

$E_d=-\dfrac{2}{3}(p^{0})$

$E_d=-\dfrac{2}{3}$

Therefore, the price elasticity of demand is -2/3.

3 0

3 years ago

Least common factor how to do in 121,99

Blizzard [7]

Answer:

Step-by-step explanation:

Prime factorize 121 and 99

121 = 11 * 11

99 = 11 * 3 * 3

Common factor = 11

6 0

3 years ago

Read 2 more answers