Answer:
(3)
Replcaing equation (3) into equation (2) we got:

And solving for Y we got:



And solving for X from equation (3) we got:

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration
Step-by-step explanation:
For this problem we can work with the concentration of water and orange juice.
Let X the amount for the orange juice with 25% content and Y the amount for the orange juice with 5% of content
Using the concentration of orange juice we have:
(1)
And for the water we have:
(2)
If we solve for X from equation (1) we got:
(3)
Replcaing equation (3) into equation (2) we got:

And solving for Y we got:



And solving for X from equation (3) we got:

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration
I need a little more to work with
Answer:
LMN has a larger area
Step-by-step explanation:
Given
RST



LMN



Required
Compare both areas
The area of triangle is:

For RST, we have:


Remove absolute signs


For LMN, we have:



Remove absolute signs


<em>By comparing both areas, we can conclude that LMN has a larger area</em>
5•3=15, 3.5•3=10.5....... the regular length of the length and width is :::::: LENGTH= 10.5 feet..... HEIGTH=15 feet