2 years ago

12 guests are coming to my party. They each get 4/5 cup of juice. How many cups of juice do I need to purchase

Mathematics

2 answers:

Rama09 [41]2 years ago

6 0

9.6 cups - 4/5 • 12 = 8/10 • 12 = 0.8 • 12 = 9.6

dusya [7]2 years ago

3 0

You would need to purchase 10 cups of juice

You might be interested in

The sum of 3 fifteens and 4 twos

iogann1982 [59]

The sum of 3 fifteens and 4 twos will be 45 +8 = 53

3 0

3 years ago

4,094 divided by 46 please help

Arlecino [84]

The answer to your question is 89

3 0

3 years ago

Read 2 more answers

What are the largest numbers for each of the following sums of three consecutive numbers: n Correct answer is brainliest

Andreyy89

Answer:

so where are the 3 consecutive numbers?

7 0

3 years ago

The diameter of a small gear is 16 cm. This is a 2.5 cm more than 1/4 of the diameter of a large gear. What is the diameter of t

eimsori [14]

The large gear has a diameter of 54 CM.

6 0

3 years ago

Read 2 more answers

From a group of 3 men and 4 women, a delegation of 2 is selected. What is the expected number of men in the delegation?

Ostrovityanka [42]

Answer:

The expected number of men in the delegation is 0.86.

Step-by-step explanation:

Number of men = 3

Number of women = 4

A delegation of 2 is selected.

Let X be the number of men selected. So, the possible values of X are 0,1,2.

$P(X=0)=\dfrac{^3C_0\times ^4C_2}{^7C_2}=\dfrac{2}{7}$

$P(X=1)=\dfrac{^3C_1\times ^4C_1}{^7C_2}=\dfrac{4}{7}$

$P(X=2)=\dfrac{^3C_2\times ^4C_0}{^7C_2}=\dfrac{1}{7}$

The expected number of men in the delegation is

$E(x)=0\times P(X=0)+1\times P(X=1)+2\times P(X=2)$

$E(x)=0\times \dfrac{2}{7}+1\times \dfrac{4}{7}+2\times \dfrac{1}{7}$

$E(x)=\dfrac{6}{7}$

$E(x)\approx 0.86$

Therefore, the expected number of men in the delegation is 0.86.

4 0

2 years ago