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4 years ago

What is the interquartile range for this set of data? 11, 19, 35, 42, 60, 72, 80, 85, 88 A) 30 B) 55.5 C) 60 D) 72

Mathematics

2 answers:

Nostrana [21]4 years ago

6 0

The answer is B) 55.5 Do you need me to work it out for you?

balandron [24]4 years ago

3 0

I think it's B. :) good luck

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andreyandreev [35.5K]

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3 years ago

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ZanzabumX [31]

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Step-by-step explanation:

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3 years ago

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Oksanka [162]

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Step-by-step explanation:

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3 years ago

In 2003, there were about 5.8078 X 10^8 people using the Internet in the world and about 1.6575 X 10^8 of these people were in t

lianna [129]

Answer:

28.5% Internet users in 2003 were in the United States.

Step-by-step explanation:

We are given the following in the question:

Number of people using the internet =

$5.8078 \times 10^8$

Number of people in United States =

$1.6575 \times 10^8$

Percent of Internet users in 2003 were in the United States =

$=\dfrac{\text{Number of users in United States}}{\text{Number of internet user in world}}\times 100\%\\\\=\dfrac{ 1.6575 \times 10^8}{5.8078 \times 10^8}\times 100\%\\\\=28.5\%$

Thus, 28.5% Internet users in 2003 were in the United States.

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4 years ago