1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
neonofarm [45]
3 years ago
8

What is the interquartile range for this set of data? 11, 19, 35, 42, 60, 72, 80, 85, 88 A) 30 B) 55.5 C) 60 D) 72

Mathematics
2 answers:
Nostrana [21]3 years ago
6 0
The answer is B) 55.5 Do you need me to work it out for you?
balandron [24]3 years ago
3 0
I think it's B. :) good luck
You might be interested in
Is the mean greater than, less than, or equal to the median? Explain your reasoning.
Alekssandra [29.7K]
Equal because 30 is the median and when you find the mean, it is also 30. Please give brainliest!
7 0
2 years ago
Explain why my calculator gives an error when you enter cos^-1 (5/4)
Gnoma [55]

Step-by-step explanation:

because the is no answer for that in the calculator

4 0
2 years ago
Read 2 more answers
Maynor rode his bike 2 miles in 8 minutes. Paul rode his bike
madam [21]

no

no because maynor rode 2 miles every 4 minutes and paul rode 3 miles every 4 minutes. not the same

7 0
3 years ago
Simplify 26-18b+11(b-3)
xxMikexx [17]

Answer:

<u>-7b-7</u>

Step-by-step explanation:

First you have to distribute 11 throughout the parentheses.

26-18b+11(b-3)\\26-18b+11b-33

Now we can combine like terms. (-18b, 11b, -33, 26)

-18b+ 11b  and -33+26

-7b-7

This is your simplified answer for your expression.

<u>-7b-7</u>

6 0
2 years ago
Read 2 more answers
Help! i just need the 3rds question, my brain is fried
Sergeeva-Olga [200]

Answer:

0.00665

0.006951

Step-by-step explanation:

If the first child is born with the affliction, there's a 0.05 probability that the second child will be born with the affliction.  Which means there's a 0.95 probability that they won't.

The probability that the first child is born with the affliction but not the second is therefore:

P = 0.007 × 0.95

P = 0.00665

There's a 0.007 probability that the first child will be born with the affliction, which means there's a 0.993 probability that they won't.  If the first child isn't born with the affliction, then the probability the second child will have it is 0.007.

So the probability that the first child is not born with the affliction and the second child is would be:

P = 0.993 × 0.007

P = 0.006951

3 0
3 years ago
Other questions:
  • An arithmetic sequence with a third term of 8 and a constant difference of 5.
    14·1 answer
  • At 7:30 a.m., a bus left Town P for Town Q at a speed of 60 kilometers per hour. 15 minutes later, a car left Town Q and headed
    5·1 answer
  • Please I’m way lost on this one need help please
    7·2 answers
  • Determine the circumference of a circle with a radius of 4 units.
    8·1 answer
  • Consider the following set of sample data.
    10·1 answer
  • 5+3 + 7 = 5 + 7 + 3 O A. True B. Fa<br>​
    6·2 answers
  • Section A
    10·1 answer
  • A.Vertical<br> B.Adjacent <br> C.complementary <br> D.Supplementary <br> E.none
    14·2 answers
  • (X + 4) + ( x + 4 ) + x + x
    8·1 answer
  • Can the sides of a triangle have lengths 3.5, 10.9, and 14.4?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!