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kolbaska11 [484]
3 years ago
14

Sam bought a used car for $8,000. He boasted that he got a great deal since the value of the car two years ago

Mathematics
1 answer:
vivado [14]3 years ago
4 0

Answer:

V(t) = 15,000*(0.75)^t

Step-by-step explanation:

The initial value is $15,000, and if it depreciates 25% per year, that means that for each year the value will be 0.75 of the value of the previous year. The next year, the value will be 0.75 of the previous, which will be o.75x0.75 of the initial value, or (0.75)².

So, for t years:

V(t) = 15,000*(0.75)^t

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So what you do is go 5(3y+5)-4y=14 which equals 15y+25-4y=14 which turns into 11y+25=14 than you move the 25 over which equals 11y=-11 so y=-1 then you enter -1 in for y which looks like 5x-4(-1)=14 than you solve that which is 5x+4=14 than you move the 4 over and you get 5x=10 than x=2

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Write an equation for the vertical line that contains point E(-12, 7). Is anybody able to help?
BigorU [14]

Answer:

x = -12

Step-by-step explanation:

Vertical lines take the form of x = something and horizontal lines take the form of y = something

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So the line x = -12 (we got -12 from the coordinate that was given to us on the question prompt) is a vertical line that passes through virtually all possible y values (from positive infinity to negative infinity, or vice-versa) which means that the question prompt having given us the y value was negligible.

Good luck!

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2 years ago
Please hellppppp asap
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Step-by-step explanation:

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3 years ago
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Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
borishaifa [10]

Answer:

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

Step-by-step explanation:

Air containing 0.04% carbon dioxide

V, volume of room is 6000 ft3.

Q, rate of air 2000 ft3/min,

initial concentration of 0.4% carbon dioxide,

determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes?

firstly, we find the time taken for air to completely filled the room

Q = V/t

t = V/Q = 6000/2000 = 3min

so, its take 3mins for air to be completely filled in the room and for exhaust air to move out.

there is  an initial concentration of 0.4% carbon dioxide, and the air pump in is 0.04%.

therefore,

3mins = 0.04% of CO2

3*60 =180sec = 0.04%

1sec = 0.04/180 = 0.00022%/sec

so at any time the concentration of CO2 is 0.4 + 0.00022 =0.40022%/sec

What is the concentration at 10 minute

the concentration at 10minutes = the concentration for 1minute because at every minutes, the concentration moves in is moves out. = concentration for 2000ft3.

for 0.04% = 6000ft3

   ?          = 2000ft3

              = 2000* 0.04)/6000 =0.0133%

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

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3 years ago
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