Answer:
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Answer:
f(g(x)) = 2x +(-5)
Step-by-step explanation:
Put the argument value into the function and simplify the result.
f(g(x)) = f(x -3) = 2(x- 3) +1 = 2x -6 +1
f(g(x)) = 2x +(-5)
Okay, so lets break this down.
First of all, we have the rectangular garden with a length of 15ft and a width of 12feet. We need to find the area of this which is pretty simple. This would be 15ft times 12ft which is 180ft².
Okay, now time for the triangle. The way that it words it may be confusing but I can draw you a picture of what it looks like (its a quick draw so it looks kinda bad).
But, for the triangle we are going to extend the 12ft line (shorter side; width) and create a line that is 7 feet long. Then, we are going to find the midpoint of the 15ft side and connect that with the end point of the triangle.
Since its on the longer side and its the midpoint, the triangle is going to have a base of 7.5ft (half of 15). Then, the height is 7ft as included in the question.
Now to solve the area of a
right triangle, you can use 1/2(bh). So 1/2 of the base times height.
This is 1/2 of (7.5*7) which is 1/2(52.5) and finally the area of the triangle is 26.25ft².
Now, all you gotta do is add the 26.25ft² and the 180ft² together and you get 206.25ft²
Answer:
V(max) = 8712.07 in³
Dimensions:
x (side of the square base) = 16.33 in
girth = 65.32 in
height = 32.67 in
Step-by-step explanation:
Let
x = side of the square base
h = the height of the postal
Then according to problem statement we have:
girth = 4*x (perimeter of the base)
and
4* x + h = 98 (at the most) so h = 98 - 4x (1)
Then
V = x²*h
V = x²* ( 98 - 4x)
V(x) = 98*x² - 4x³
Taking dervatives (both menbers of the equation we have:
V´(x) = 196 x - 12 x² ⇒ V´(x) = 0
196x - 12x² = 0 first root of the equation x = 0
Then 196 -12x = 0 12x = 196 x = 196/12
x = 16,33 in ⇒ girth = 4 * (16.33) ⇒ girth = 65.32 in
and from equation (1)
y = 98 - 4x ⇒ y = 98 -4 (16,33)
y = 32.67 in
and maximun volume of a carton V is
V(max) = (16,33)²* 32,67
V(max) = 8712.07 in³
The index of the root 3 is an odd number, then x can be either positive or negative, then
Domain of the function = R = (-Infinitive, Infinitive)
R. All real numbers
Answer: First option -Infinitive < x < Infinitive