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photoshop1234 [79]

3 years ago

13

The surface area of a globe in Mr. Patton's classroom is about 152.39 square inches. Find its

1 answer:

Snezhnost [94]3 years ago

6 0

Answer:

176.89in^3

Step-by-step explanation:

when finding the volume using the surface area, the best method that comes in my mind is finding the ratio between the surface area and volume which would be r/3 for a sphere. So if given that the surface area of the sphere is 152.39 square r/3=around 1.161, and when multiplied by 152.39 is around 176.89. another similar method is deriving the radius when given its surface area which is simply taking the square root of the surface area/4pi which turns out to be 3.482357088 or 3.48 which can then be plugged into the volume formula as the radius which is (3.48^3*4pi)/3 which turns out to be the same answer!

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Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = 7 divided by q and tan y° =

Andre45 [30]

Answer:

Cosy° = $\frac{r}{q}$

Step-by-step explanation:

From the picture attached,

By applying all trigonometric ratios in the given right triangle,

Siny° = $\frac{7}{q}$ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

tany° = $\frac{7}{r}$ = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

Therefore, Cosy° = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

Cosy° = $\frac{r}{q}$

Therefore, Cosy° = $\frac{r}{q}$ will be the answer.

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4 years ago

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Artyom0805 [142]

She sold 225 pieces of pie last week.

8 0

4 years ago

Expression that has a value of 2.472.

Monica [59]

Answer 4.6/5. 20

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3 0

3 years ago

Vanessa draws one side of equilateral ΔABC on the coordinate plane at points A(–2, 1) and B(4,1). Select all the possible coordi

Radda [10]

(1, $\sqrt{27}$ ) and (1, - $\sqrt{27}$ )

Step-by-step explanation:

Step 1 :

The co ordinates of the given equilateral triangle are A(-2,1) and B(4,1)

The distance between these 2 points is the length of the given triangle

Distance between the 2 points is $\sqrt{(x2-x1)^{2}+ (y2-y1)^{2}}$ = sqrt (sq(4-(-2)) + sq(1-1)) = 6

Hence the given triangle has 3 equal side of length 6 unit.

Step 2:

The length of the other side should be 6. Let (x,y) be the co-ordinate of the point C

We have then x = 1 (because the perpendicular from C to AB bisects AB we have the point C to have the x co-ordinate as 1)

Also we have the distance between the point B(4,1) and C(1,y) to be 6 as this is an equilateral triangle

Hence $\sqrt{(4-1)^{2} + (1-y)^{2 }$ = 6

=> 9 + 1 + $y^{2}$ -2 y = 6

=> $y^{2}$ -2 y - 26 = 0

=> y = 2± sqrt(4+104) / 2 = 1 ± sqrt(27)

Hence the possible co ordinates of C are (1, $\sqrt{27}$ ) and (1, - $\sqrt{27}$ )

3 0

4 years ago

A spinner has 4 equal-sized sections labeled A, B, C, and D. It is spun and a fair coin is tossed. What is the probability of sp

allsm [11]

Probability of spinning a C =1/4
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8 0

2 years ago