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3 years ago

What is the sum of 2 / 3x^2 +12x and 8 / c. Need steps

Mathematics

1 answer:

Marta_Voda [28]3 years ago

5 0

Answer:

$\frac{2c}{3x^2c}+ \frac{36x^3c}{3x^2c} +\frac{24x^2}{3x^2c} [\tex]Step-by-step explanation:We need to find sum of 2 / 3x^2 +12x and 8 / cSo, solving:[tex](\frac{2}{3x^2} + 12 x ) +\frac{8}{c}$

Taking LCM of 3x^2 and 1 i.e. 3x^2

$=(\frac{2 + 12 x(3x^2)}{3x^2} ) +\frac{8}{c}\\=(\frac{2 + 36x^3}{3x^2} ) +\frac{8}{c}\\=\frac{2 + 36x^3}{3x^2} +\frac{8}{c}\\LCM \,\, 36x^2 c\\=\frac{(2 + 36x^3)c + 8(3x^2)}{3x^2c}\\=\frac{2c + 36x^3c + 24x^2}{3x^2c}\\= \frac{2c}{3x^2c}+ \frac{36x^3c}{3x^2c} +\frac{24x^2}{3x^2c}$

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$3 = \frac{4}{5} (-1) +C$

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$C =\frac{19}{5}$

so c) is $y = \frac{4}{5} x+\frac{19}{5}$

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